Suppose 25 children who weigh the same are playing a game of tug-of-war. Five children pull with 10 newtons of force, while ten children pull with 15 newtons of force in the opposite direction. How can one determine the net force on the rope?(1 point)
Responses
The forces are in the same direction, so the newtons can be added.
The forces are in the same direction, so the newtons can be added.
The newtons are in the same direction, so the newtons can be multiplied.
The newtons are in the same direction, so the newtons can be multiplied.
The forces are in opposite directions, so the newtons can be subtracted.
The forces are in opposite directions, so the newtons can be subtracted.
The forces are in opposite directions, so the newtons can be divided.
The forces are in opposite directions, so the newtons can be divided.
The forces are in opposite directions, so the newtons can be subtracted.
The net force on the rope can be determined by subtracting the forces in opposite directions. Therefore, the correct answer is "The forces are in opposite directions, so the newtons can be subtracted."
To determine the net force on the rope, you need to consider both the direction and magnitude of the forces applied. In this scenario, there are two opposing forces: 10 newtons exerted by five children and 15 newtons exerted by ten children in the opposite direction.
To find the net force, you can subtract the force exerted in one direction from the force exerted in the opposite direction. This can be represented as:
Net force = Force in one direction - Force in the opposite direction
In this case, the net force would be:
Net force = 15 newtons - 10 newtons
Calculating the difference, the net force exerted on the rope would be 5 newtons, in the direction of the group pulling with the greater force.