Factor completely.
81, minus, 49, x, squared
81−49x
2
There seems to be an error in the expression you provided. It should be 81 - 49x^2, not 81 - 49x.
To factor completely, we can recognize that it is in the form of the difference of squares.
We can write it as (9)^2 - (7x)^2, which can be factored as (9 - 7x)(9 + 7x).
So the completely factored expression is (9 - 7x)(9 + 7x).
To factor the expression 81 - 49x^2 completely, we can use the difference of squares pattern. The difference of squares pattern states that for any expression in the form a^2 - b^2, it can be factored into (a + b)(a - b).
In this case, a = 9 and b = 7x. Hence, we can factor 81 - 49x^2 as follows:
81 - 49x^2 = (9 + 7x)(9 - 7x)
Therefore, the expression is factored completely as (9 + 7x)(9 - 7x).
To factor the expression 81 - 49x, we need to identify any common factors that can be factored out from both terms.
In this case, we can see that both terms have a factor of 7. So, let's factor out 7:
7(81/7 - 49x/7)
Now, we simplify further:
7(9 - 7x)
And that is the completely factored form of the expression 81 - 49x.