Factor.
x, squared, plus, 2, x, minus, 15
x
2
+2x−15
To factor the expression x^2 + 2x - 15, we need to find two numbers whose product is -15 and whose sum is 2.
The numbers that satisfy these conditions are 5 and -3, since 5 * -3 = -15 and 5 + -3 = 2.
Now we can rewrite the expression as:
x^2 + 5x - 3x - 15
Next, we group the terms and factor by grouping:
(x^2 + 5x) - (3x + 15)
x(x + 5) - 3(x + 5)
Finally, we can factor out the common binomial (x + 5):
(x + 5)(x - 3)
Therefore, the factored form of x^2 + 2x - 15 is (x + 5)(x - 3).
To factor the expression x^2 + 2x - 15, we need to find two numbers that multiply to -15 and add up to 2.
The numbers that meet these criteria are 5 and -3.
Now let's rewrite the expression using these numbers:
x^2 + 5x - 3x - 15
Next, we'll group the terms:
(x^2 + 5x) + (-3x - 15)
Now we can factor out a common factor from each group:
x(x + 5) - 3(x + 5)
Notice that we now have a common binomial factor of (x + 5).
So, we can rewrite the expression as:
(x - 3)(x + 5)
Therefore, the factored form of x^2 + 2x - 15 is (x - 3)(x + 5).
To factor the expression x^2 + 2x - 15, we need to find two numbers whose sum is 2 and product is -15.
One way to do this is by identifying two numbers, let's call them a and b, such that a + b = 2 and a * b = -15.
To find these numbers, we can try different combinations until we get the desired result. Let's start with a = 5 and b = -3:
a + b = 5 + (-3) = 2 (Sum is correct)
a * b = 5 * (-3) = -15 (Product is correct)
Therefore, we can rewrite the original expression x^2 + 2x - 15 as follows:
x^2 + 5x - 3x - 15
Now, we group the expression into two pairs:
(x^2 + 5x) + (-3x - 15)
Next, we factor out the greatest common factor from each pair:
x(x + 5) - 3(x + 5)
Notice that both terms inside the parentheses are the same, (x + 5). We can then factor this common binomial out:
(x - 3)(x + 5)
So, the factored form of the expression x^2 + 2x - 15 is (x - 3)(x + 5).