What would be the time taken for a collision between a car, of mass 850kg, travelling
at 17 km/h and a wall, if the force involved was 3700N before the car came to a
complete stop? Give your answer to 2 decimal places.
To find the time taken for the collision, we can use Newton's second law of motion, which states that force is equal to mass multiplied by acceleration:
Force = mass * acceleration
In this case, the force involved is 3700N and the mass of the car is 850kg. We need to find the acceleration.
Rearranging the equation, we have:
acceleration = force / mass
acceleration = 3700N / 850kg
acceleration ≈ 4.35 m/s²
Now, we can use the equation for acceleration to find the time taken for the car to come to a complete stop.
We know the initial velocity of the car is 17 km/h, which is 4.72 m/s.
The final velocity is 0 m/s since the car comes to a complete stop.
Using the equation:
final velocity = initial velocity + (acceleration * time)
0 m/s = 4.72 m/s + (4.35 m/s² * time)
Rearranging the equation, we have:
4.72 m/s = 4.35 m/s² * time
time = 4.72 m/s / 4.35 m/s²
time ≈ 1.08 seconds
Therefore, the time taken for the collision is approximately 1.08 seconds.
To find the time taken for the collision, we can use the equation:
Force = mass x acceleration
Rearranging the equation to solve for acceleration:
acceleration = Force / mass
We know the force involved in the collision is 3700N, and the mass of the car is 850kg. Plugging these values into the equation:
acceleration = 3700N / 850kg
acceleration ≈ 4.35 m/s²
We also know that the car was initially traveling at 17 km/h. To convert this to meters per second (m/s), we use the conversion factor 1 km/h = 0.2778 m/s:
initial velocity = 17 km/h x 0.2778 m/s
initial velocity ≈ 4.72 m/s
The car comes to a complete stop, so the final velocity is 0 m/s.
Using the equation for acceleration, final velocity, initial velocity, and time:
final velocity = initial velocity + acceleration x time
0 m/s = 4.72 m/s + 4.35 m/s² x time
Solving for time:
4.35 m/s² x time = -4.72 m/s
time = -4.72 m/s / 4.35 m/s²
time ≈ -1.08 s
Since time cannot be negative in this context, we can take the absolute value of the result:
time ≈ 1.08 s
Therefore, the time taken for the collision between the car and the wall would be approximately 1.08 seconds.
To find the time taken for a collision between a car and a wall, we can use Newton's second law of motion, which states that the force acting on an object is equal to the product of its mass and its acceleration:
Force = Mass * Acceleration
In this case, the force acting on the car is 3700N, and the mass of the car is 850kg. The car initially travels at a speed of 17 km/h, but comes to a complete stop during the collision. Therefore, we need to calculate the deceleration (negative acceleration) of the car.
First, we need to convert the speed from km/h to m/s, since the SI unit for acceleration is meters per second squared (m/s^2).
1 km = 1000 m
1 hour = 3600 seconds
So, 17 km/h = (17 * 1000) / 3600 = 4.72 m/s (rounded to 2 decimal places).
Now we can calculate the acceleration using the following formula:
Acceleration = (Final Velocity - Initial Velocity) / Time
The initial velocity is 4.72 m/s, the final velocity is 0 m/s (since the car comes to a complete stop), and the time is what we need to find.
Rearranging the formula, we have:
Time = (Final Velocity - Initial Velocity) / Acceleration
Substituting the values:
Time = (0 - 4.72) / Acceleration
To find the acceleration, we can use Newton's second law:
Acceleration = Force / Mass
Substituting the given values, we have:
Acceleration = 3700 / 850
Now we can substitute the acceleration into the time formula:
Time = (0 - 4.72) / (3700 / 850)
Calculating this, the time would be approximately -1.18432 seconds (rounded to 2 decimal places).
However, a negative time does not make physical sense in this context. Therefore, we can conclude that the car would not collide with the wall in this scenario, as the given force and mass are not realistic for a collision to occur.