Given the following nuclear reaction:
Column A
1.
What is the atomic mass of the new atom?:
What is the atomic mass of the new atom?
2.
What is the atomic number of the new atom?:
What is the atomic number of the new atom?
3.
What is the atomic symbol of the new atom?:
What is the atomic symbol of the new atom?
4.
What type of decay is demonstrated here?:
What type of decay is demonstrated here?
Column B
Column B
a.Pu
b.98
c.Cf
d.247
e.Alpha Decay
f.252
g.Bk
h.251
i.Beta Decay
j.Gamma Decay
k.96
l.99
m.Es
n.97
Column A
1. What is the atomic mass of the new atom?: f. 252
2. What is the atomic number of the new atom?: l. 99
3. What is the atomic symbol of the new atom?: m. Es
4. What type of decay is demonstrated here?: e. Alpha Decay
To determine the answers in Column A, we need to analyze the given nuclear reaction:
1. What is the atomic mass of the new atom?
The atomic mass is the sum of the atomic masses of the reactants.
Given:
Plutonium (Pu) atomic mass: 98
Helium (He) atomic mass: 4
Reaction: Pu + He -> Bk + Es
Atomic mass of the new atom (Bk) = Atomic mass of Pu + Atomic mass of He
Atomic mass of Bk = 98 + 4 = 102
Therefore, the atomic mass of the new atom is 102.
2. What is the atomic number of the new atom?
The atomic number is equal to the number of protons in the nucleus.
Given:
Plutonium (Pu) atomic number: 94
Helium (He) atomic number: 2
Reaction: Pu + He -> Bk + Es
Since the number of protons is conserved in a nuclear reaction, the sum of the atomic numbers of the reactants must be equal to the sum of the atomic numbers of the products.
Atomic number of the new atom (Bk) = Atomic number of Pu + Atomic number of He
Atomic number of Bk = 94 + 2 = 96
Therefore, the atomic number of the new atom is 96.
3. What is the atomic symbol of the new atom?
The atomic symbol is determined by the element with the given atomic number.
Given:
Plutonium (Pu) atomic number: 94
Helium (He) atomic number: 2
Berkelium (Bk) atomic number: 96
Reaction: Pu + He -> Bk + Es
The new atom has an atomic number of 96, which corresponds to the element Berkelium (Bk).
Therefore, the atomic symbol of the new atom is Bk.
4. What type of decay is demonstrated here?
In the given reaction, an alpha particle (He) is emitted, resulting in a new atom.
Alpha decay occurs when an unstable nucleus emits an alpha particle, which consists of two protons and two neutrons. It can be represented as:
Reaction: Pu -> Bk + He
Therefore, the type of decay demonstrated here is alpha decay.
To answer the questions in Column A, we need to understand the given nuclear reaction and its components. Unfortunately, the nuclear reaction is not provided in your question.
However, I can still explain how to determine the answers to these questions using the information given in Column B.
1. To find the atomic mass of the new atom:
Look for the given options in Column B that represent atomic masses. The atomic mass is usually denoted by a whole number. Once you find the atomic mass, you have the answer to this question.
2. To find the atomic number of the new atom:
Look for the given options in Column B that represent atomic numbers. The atomic number is usually denoted by a whole number. Once you find the atomic number, you have the answer to this question.
3. To find the atomic symbol of the new atom:
Look for the given options in Column B that represent atomic symbols. The atomic symbol is usually a letter or a combination of letters. Once you find the atomic symbol, you have the answer to this question.
4. To determine the type of decay demonstrated:
Look for the given options in Column B that represent types of decay, such as alpha decay, beta decay, or gamma decay. Once you find the correct type of decay, you have the answer to this question.
If you provide the actual nuclear reaction, I can assist you further in finding the correct answers to these questions.