Given the following nuclear reaction:
223/87fr>0/-1e+a/zx
Column A
1.
What is the atomic mass of the new atom?:
What is the atomic mass of the new atom?
2.
What is the atomic number of the new atom?:
What is the atomic number of the new atom?
3.
What is the symbol of the new atom?:
What is the symbol of the new atom?
4.
What type of decay is demonstrated here?:
What type of decay is demonstrated here?
Column B
Column B
a.222
b.86
c.224
d.Beta Decay
e.Gamma Decay
f.Ac
g.Alpha Decay
h.88
i.Fr
j.223
k.Ra
l.89
m.87
Column A:
1. 222
2. 86
3. Ra
4. Alpha Decay
Column B:
1. c
2. b
3. k
4. g
Column A
1. The atomic mass of the new atom is 224.
1. To determine the atomic mass of the new atom, you need to sum up the atomic masses of the particles involved in the reaction. The atomic mass of 223/87 Fr is given in the question as 223, and the atomic mass of a 0/-1 e (electron) is negligible since its mass is very small compared to the nucleus. Since the alpha particle is also involved in the reaction, you need to know its atomic mass. The symbol of the alpha particle is 4/2 He, which means it has an atomic mass of 4. Adding the atomic masses, you get: 223 + 4 = 227.
Therefore, the atomic mass of the new atom is 227 (option c in column B).
2. The atomic number of an atom represents the number of protons in its nucleus. In the given reaction, the atomic number of the original atom 223/87 Fr is 87 since it is the subscript of the element symbol. The electron (0/-1 e) does not contribute to the atomic number since it is not a proton. The alpha particle, however, consists of two protons. Therefore, when it is emitted, the atomic number of the new atom will decrease by 2.
Hence, the atomic number of the new atom is 87 - 2 = 85 (option b in column B).
3. The symbol of the new atom is determined by its atomic number. In the question, the original atom Fr has an atomic number of 87. As calculated in the previous step, the atomic number of the new atom is 85. To find the element with atomic number 85, you can refer to the periodic table. Element number 85 is Astatine (At).
So, the symbol of the new atom is At (option i in column B).
4. The type of decay demonstrated in the given nuclear reaction is determined by the emitted particle. The reaction shows the emission of an alpha particle (4/2 He) and an electron (0/-1 e).
Alpha decay occurs when an unstable nucleus emits an alpha particle, consisting of two protons and two neutrons (helium nucleus).
Beta decay occurs when an unstable nucleus emits an electron (beta particle) or a positron (positively charged electron).
Gamma decay involves the emission of gamma rays, which are high-energy photons emitted when the nucleus transitions to a lower energy state.
In this reaction, the emitted alpha particle indicates that alpha decay is demonstrated here (option g in column B).
So the answers are:
1. Atomic mass of the new atom: c. 224
2. Atomic number of the new atom: b. 86
3. Symbol of the new atom: i. At
4. Type of decay demonstrated: g. Alpha Decay