If the temperature of 15 g of aluminum increases from 20 to 350 C, how much heat is absorbed (specific heat of aluminum = 0.897 J/gC)
To calculate the heat absorbed, you can use the formula:
Q = m * c * ΔT
Where:
Q = heat absorbed (in joules)
m = mass of the substance (in grams)
c = specific heat capacity of the substance (in J/g°C)
ΔT = change in temperature (in °C)
Given:
m (mass of aluminum) = 15 g
c (specific heat capacity of aluminum) = 0.897 J/g°C
ΔT (change in temperature) = 350°C - 20°C = 330°C
Substituting these values into the formula:
Q = 15 g * 0.897 J/g°C * 330°C
Q = 448.5 J
Therefore, 15 g of aluminum absorbed 448.5 J of heat.
To determine the amount of heat absorbed by the aluminum, we can use the formula:
Q = m * c * ΔT
Where:
Q is the heat absorbed (in Joules),
m is the mass of the object (in grams),
c is the specific heat capacity of the material (in J/g°C), and
ΔT is the change in temperature (in °C).
Given:
m = 15 g (mass of aluminum)
c = 0.897 J/g°C (specific heat capacity of aluminum)
ΔT = 350°C - 20°C = 330°C (change in temperature)
Now, we can substitute these values into the formula:
Q = 15 g * 0.897 J/g°C * 330°C
Calculating this expression:
Q = 4485 J
Therefore, 15 g of aluminum absorbs 4485 Joules of heat when its temperature increases from 20°C to 350°C.
To calculate the amount of heat absorbed by the aluminum, you need to use the formula:
Heat Absorbed = mass × specific heat × change in temperature
Given:
Mass (m) = 15 g
Specific heat (c) = 0.897 J/gC
Change in temperature (ΔT) = 350 C - 20 C = 330 C
Now, plug the values into the formula to calculate the heat absorbed:
Heat Absorbed = 15 g × 0.897 J/gC × 330 C
First, multiply the mass (15 g) by the specific heat (0.897 J/gC):
15 g × 0.897 J/gC = 13.455 J/C
Then, multiply this result by the change in temperature (330 C):
13.455 J/C × 330 C = 4,435.65 J
Therefore, the amount of heat absorbed by the aluminum is approximately 4,435.65 Joules (J).