An intravenous saline solution contains 147 mEq/L each of Na+ and CI-
How many moles of CI- are in 0.700 L of the saline solution?
To find the number of moles of Cl- in 0.700 L of the saline solution, we first need to calculate the concentration of Cl- in moles per liter.
Since the concentration of Cl- is 147 mEq/L, and 1 mole is equal to 1000 milliequivalents, we can convert the concentration to moles per liter:
Concentration of Cl- = 147 mEq/L * (1 mole / 1000 milliequivalents) = 0.147 moles/L
Now we can calculate the number of moles of Cl- in 0.700 L of the saline solution:
Number of moles of Cl- = Concentration of Cl- * Volume of solution
= 0.147 moles/L * 0.700 L
= 0.1029 moles
Therefore, there are approximately 0.1029 moles of Cl- in 0.700 L of the saline solution.
To find the number of moles of CI- in the saline solution, we need to use the given information about the concentration of CI- and the volume of the solution.
First, let's convert the concentration of CI- from milliequivalents per liter (mEq/L) to moles per liter (mol/L). The atomic mass of CI is about 35.45 g/mol.
The concentration of CI- in the solution is 147 milliequivalents (mEq) per liter (L). To convert this to moles:
1. Convert milliequivalents to equivalents: 147 mEq x (1/1000) = 0.147 Eq
2. Convert equivalents to moles: 0.147 Eq x (1 mol/1 Eq) = 0.147 mol
Now that we have the concentration of CI- in moles per liter (mol/L), we can calculate the number of moles in 0.700 L of the saline solution.
Number of moles of CI- = Concentration of CI- x Volume of the solution
= 0.147 mol/L x 0.700 L
= 0.1029 mol
Therefore, there are approximately 0.1029 moles of CI- in 0.700 L of the saline solution.
To find the number of moles of Cl- in 0.700 L of the saline solution, we need to use its concentration and the volume of the solution.
Given:
- Concentration of Cl- in the saline solution = 147 mEq/L
- Volume of the saline solution = 0.700 L
To find the number of moles, we'll first convert the concentration from milliequivalents per liter (mEq/L) to moles per liter (mol/L). The molar mass of Cl- is 35.5 g/mol.
1. Convert concentration from mEq/L to mol/L:
Since the mEq/L unit is based on the charge of the ion, we need to convert it to moles using the concept of equivalent weights.
The equivalent weight of Cl- is the same as its molar mass, which is 35.5 g/mol.
Conversion factor: 1 mEq/L = 0.0355 mol/L
Therefore, the concentration of Cl- in mol/L would be:
Concentration of Cl- = 147 mEq/L × 0.0355 mol/L = 5.2285 mol/L
2. Calculate the number of moles in 0.700 L of the saline solution:
Number of moles of Cl- = Concentration of Cl- × Volume of solution
Number of moles of Cl- = 5.2285 mol/L × 0.700 L = 3.66095 moles
Rounding to an appropriate number of significant figures, the number of moles of Cl- in 0.700 L of the saline solution is approximately 3.66 moles.