An intravenous saline solution contains 147 mEq/L each of Na+ and CI-
How many moles of Na+ are in 0.700 L of the saline solution?
To calculate the number of moles of Na+ in 0.700 L of the saline solution, we need to multiply the concentration of Na+ (147 mEq/L) by the volume of solution (0.700 L) and then convert from milliequivalents (mEq) to moles.
Step 1: Calculate the amount of Na+ in milliequivalents (mEq).
Concentration of Na+ in the saline solution = 147 mEq/L
Volume of saline solution = 0.700 L
Amount of Na+ in mEq = concentration * volume
= 147 mEq/L * 0.700 L
= 102.9 mEq
Step 2: Convert mEq to moles.
1 mole of Na+ = 1 equivalent (Eq)
1 mEq = 1/1000 Eq
So, 102.9 mEq = 102.9/1000 Eq
To calculate the number of moles, we divide by the Faraday constant (F), which is approximately equal to 96485 C/mol.
Number of moles of Na+ = (102.9/1000 Eq) / 96485 C/mol
= 0.001066 mol
Therefore, there are approximately 0.001066 moles of Na+ in 0.700 L of the saline solution.
To find the number of moles of Na+ in the saline solution, you need to multiply the concentration of Na+ by the volume of the solution.
First, convert the concentration of Na+ from milliequivalents per liter (mEq/L) to moles per liter (mol/L) by dividing by the atomic weight of Na+:
1 mole Na+ = 23 g (atomic weight of Na+)
1 milliequivalent Na+ = 0.001 moles Na+
So the concentration of Na+ in moles per liter is:
(147 mEq/L) x (0.001 mol/mEq) = 0.147 mol/L
Next, multiply the concentration by the volume of the solution:
(0.147 mol/L) x (0.700 L) = 0.1029 moles
Therefore, there are approximately 0.1029 moles of Na+ in 0.700 L of the saline solution.
To determine the number of moles of Na+ in the saline solution, we need two pieces of information: the concentration of Na+ in the solution (given as 147 mEq/L) and the volume of the solution (given as 0.700 L).
Step 1: Convert the concentration from milliequivalents (mEq) to moles.
The molarity (M) of a solution can be converted to moles per liter (mol/L) by dividing by the molar mass of the species. Since the molar mass of Na+ is 22.99 g/mol, we can convert mEq/L to mol/L as follows:
1 mEq/L = 0.001 mol/22.99 g = 0.001/22.99 mol/g
Step 2: Calculate the number of moles of Na+ in the given volume.
To determine the number of moles of Na+ in the solution, we can multiply the concentration in moles per liter (mol/L) by the volume in liters (L):
Number of moles of Na+ = Concentration (mol/L) × Volume (L)
Now, substituting the given values:
Number of moles of Na+ = 147 mEq/L × 0.001/22.99 mol/g × 0.700 L
Simplifying this expression will give us the answer.