Professor Harrington took a sample of metal and measured how many kilograms of each metal were present. The professor found 14.52 kilograms of aluminum, 9.9 kilograms of lead, and 1.137 kilograms of silver. How many kilograms was Professor Harrington's sample?
The total weight of the sample is the sum of the weights of the individual metals.
Total weight = 14.52 kg + 9.9 kg + 1.137 kg
Total weight = 25.557 kg
Professor Harrington's sample weighed 25.557 kilograms.
To find the total mass of Professor Harrington's sample, we need to add up the masses of aluminum, lead, and silver.
Mass of aluminum = 14.52 kilograms
Mass of lead = 9.9 kilograms
Mass of silver = 1.137 kilograms
Total mass = Mass of aluminum + Mass of lead + Mass of silver
Total mass = 14.52 kilograms + 9.9 kilograms + 1.137 kilograms
Total mass = 25.557 kilograms
Therefore, Professor Harrington's sample weighed 25.557 kilograms.
To find the total weight of Professor Harrington's sample, you can simply add up the weights of the individual metals.
In this case, the amounts of aluminum, lead, and silver are given as 14.52 kilograms, 9.9 kilograms, and 1.137 kilograms respectively.
To find the total weight, you add these values together:
14.52 + 9.9 + 1.137 = 25.557 kilograms
Therefore, Professor Harrington's sample weighs approximately 25.557 kilograms.