A50kg sample of unknown metal warms from 18°to 58° after absorbing 800 joules what is the specific heat of the metal in j/kg C
To find the specific heat (c) of the metal in J/kg°C, we can use the formula:
Q = mcΔT
Where:
- Q is the heat energy absorbed by the metal in joules (given as 800 J)
- m is the mass of the metal in kilograms (given as 50 kg)
- c is the specific heat of the metal in J/kg°C (what we want to find)
- ΔT is the change in temperature in degrees Celsius (final temperature minus initial temperature)
First, let's calculate the change in temperature:
ΔT = final temperature - initial temperature
ΔT = 58°C - 18°C
ΔT = 40°C
Now we can rearrange the formula and solve for c:
c = Q / (m * ΔT)
c = 800 J / (50 kg * 40°C)
c = 800 J / (2000 kg°C)
c = 0.4 J/kg°C
Therefore, the specific heat of the metal is 0.4 J/kg°C.