Claire works two jobs; she works 54 hours in one week with these two jobs and makes $10 an hour. She is trying to save up for a trip that cost her $5000. She has set aside $1500 already. Write an inequality to represent the minimum amount of weeks she needs to work to save at least 5000. (1 point)
Responses
54(10)x−1500≤5000
54 10 x minus 1500 is less than or equal to 5000
10x+1500≥5000
10 x plus 1500 is greater than or equal to 5000
54(10)x+1500≥5000
54 10 x plus 1500 is greater than or equal to 5000
10x+1500≤5000
10 x plus 1500 is less than or equal to 5000
10x + 1500 ≤ 5000
To solve this problem, we need to calculate the total amount of money Claire can make in a week from working both jobs.
Claire works 54 hours in one week, and her hourly wage is $10. So her total earnings in one week can be calculated as 54 * 10 = $540.
Since Claire has already set aside $1500, we need to find the minimum number of weeks, represented by x, needed to save at least $5000.
To find the minimum number of weeks, we can set up an inequality using Claire's earnings and the amount she needs to save:
10x + 1500 ≥ 5000
This means that Claire's earnings (10x) plus the amount she has already set aside (1500) should be greater than or equal to $5000.
So the correct inequality to represent the minimum amount of weeks Claire needs to work to save at least $5000 is:
10x + 1500 ≥ 5000