The population of a city is given as 3.45x10^6. A nearby city has a population of 1.3x10^5.
What is the sum of the populations of the two cities in scientific notation?
To find the sum of the populations of the two cities in scientific notation, we have to make the exponents of the powers of 10 the same.
The population of the first city is 3.45x10^6.
The population of the second city is 1.3x10^5.
To make the exponents the same, we need to convert the population of the second city to scientific notation with an exponent of 6.
1.3x10^5 can be rewritten as 0.13x10^6.
Now we can add the populations:
3.45x10^6 + 0.13x10^6 = 3.58x10^6
Therefore, the sum of the populations of the two cities in scientific notation is 3.58x10^6. Answer: \boxed{3.58x10^6}.
To find the sum of the populations of the two cities in scientific notation, you need to add the numbers and adjust the result to be in scientific notation.
First, let's add the numbers: 3.45x10^6 + 1.3x10^5.
To make adding the numbers easier, you need to align the exponents. In this case, you can multiply 1.3 by 10^6 to match the exponent of 3.45.
So, 3.45x10^6 + 1.3x10^5 becomes (3.45 + 0.13)x10^6.
Now, add the numbers: 3.45 + 0.13 = 3.58.
Finally, express the sum in scientific notation: 3.58x10^6.
Therefore, the sum of the populations of the two cities in scientific notation is 3.58x10^6.
To find the sum of the populations of the two cities in scientific notation, we cannot simply add the numbers as they are. We need to convert them to the same power of 10.
The population of the first city is 3.45 x 10^6.
The population of the second city is 1.3 x 10^5.
To convert 3.45 x 10^6 to the same power of 10 as 1.3 x 10^5, we need to move the decimal point to the left by 1 place.
So, 3.45 x 10^6 can be written as 34.5 x 10^5.
Now we can add the populations:
34.5 x 10^5 + 1.3 x 10^5
To add these numbers, we need to ensure that they have the same power of 10. In this case, they both have 10^5 as the power of 10.
So, the sum of the populations of the two cities is (34.5 + 1.3) x 10^5.
Simplifying the expression further, we get:
35.8 x 10^5.
Therefore, the sum of the populations of the two cities in scientific notation is 3.58 x 10^6.
An empty dumb truck weighs about 2.8x10^5 pounds. How much does it weigh if 15,300 pounds of trash is added? The answer should be in scientific notation.
To find the weight of the dump truck with the trash added in scientific notation, we need to add the weights of the empty dump truck and the trash.
The weight of the empty dump truck is 2.8x10^5 pounds.
The weight of the trash added is 15,300 pounds.
Adding these weights gives:
2.8x10^5 + 15,300 = 2.8x10^5 + 1.53x10^4
Now, to add these numbers, we need to make the exponents of 10 the same.
10^5 is already in the same form, so we don't need to do anything.
Now we can add the numbers:
2.8x10^5 + 1.53x10^4 = (2.8 + 0.153)x10^5
Simplifying the expression further, we get:
2.953 x 10^5
Therefore, the weight of the dump truck with the trash added in scientific notation is 2.953 x 10^5 pounds.
a half-life of uranium-235 is 700,000,000 years. The half-life of uranium-238 is 4.463x10^11 years longer. What is the half-life of uranium-238? The answer should be in decimal form.
To find the half-life of uranium-238, we need to add the additional half-life to the half-life of uranium-235.
The half-life of uranium-235 is given as 700,000,000 years.
The additional half-life for uranium-238 is stated as 4.463x10^11 years longer.
To find the half-life of uranium-238, we add the additional half-life to the half-life of uranium-235:
700,000,000 + 4.463x10^11
To add these numbers, we need to convert 700,000,000 to scientific notation:
700,000,000 = 7x10^8
Now, with both numbers in scientific notation, we can add them:
7x10^8 + 4.463x10^11
Since both numbers have the same base (10), we can add them by keeping the base and adding the coefficients:
(7 + 4.463)x10^11
This simplifies to:
11.463x10^11
Therefore, the half-life of uranium-238 is approximately 11.463x10^11 years. In decimal form, this is 11,463,000,000,000 years or 11.463 trillion years.