Calculate the heat energy required to raise the temperature of 6.0kg of allumioum from 20c to 60
To calculate the heat energy required to raise the temperature of aluminum, we can use the equation:
Q = mcΔT
Where:
- Q is the heat energy (in joules)
- m is the mass of the aluminum (in kg)
- c is the specific heat capacity of aluminum (in J/kg°C)
- ΔT is the change in temperature (in °C)
First, we need to find the specific heat capacity of aluminum. The specific heat capacity of aluminum is approximately 0.897 J/g°C, which is equivalent to 897 J/kg°C.
Next, we can substitute the given values into the equation:
Q = (6.0 kg) * (897 J/kg°C) * (60°C - 20°C)
Q = (6.0 kg) * (897 J/kg°C) * (40°C)
Q ≈ 215,280 J
Therefore, approximately 215,280 joules of heat energy are required to raise the temperature of 6.0 kg of aluminum from 20°C to 60°C.
To calculate the heat energy required to raise the temperature of a substance, you can use the formula:
Q = m * c * ΔT
Where:
Q = Heat energy (in joules)
m = Mass of the substance (in kilograms)
c = Specific heat capacity of the substance (measured in joules per kilogram per degree Celsius)
ΔT = Change in temperature (final temperature - initial temperature)
In this case, we want to calculate the heat energy required to raise the temperature of 6.0kg of aluminum from 20°C to 60°C.
First, we need to determine the specific heat capacity of aluminum. The specific heat capacity of aluminum is approximately 900 J/(kg°C).
Next, we can substitute the values into the formula:
Q = 6.0 kg * 900 J/(kg°C) * (60°C - 20°C)
Calculating the values:
Q = 6.0 kg * 900 J/(kg°C) * 40°C
Q = 216,000 J
Therefore, the heat energy required to raise the temperature of 6.0kg of aluminum from 20°C to 60°C is 216,000 joules.
To calculate the heat energy required to raise the temperature of a substance, we need to use the specific heat capacity equation:
Q = mcΔT
Where:
Q is the heat energy
m is the mass of the substance
c is the specific heat capacity of the substance
ΔT is the change in temperature
For aluminum, the specific heat capacity (c) is approximately 0.897 J/g°C or 0.897 J/gK.
First, convert the mass from kilograms to grams:
6.0 kg = 6.0 * 1000 g = 6000 g
Next, calculate the change in temperature:
ΔT = Final temperature - Initial temperature
ΔT = 60°C - 20°C = 40°C
Now we can calculate the heat energy using the formula:
Q = mcΔT
Q = (6000 g) * (0.897 J/g°C) * (40°C)
Q = 215,280 J
Therefore, the heat energy required to raise the temperature of 6.0 kg of aluminum from 20°C to 60°C is 215,280 Joules.