Calculate the amount of heat required to raise the temperature of a 39 g sample of water from 9 ∘C to 21 ∘C
Use the formula Q=m*C*change in T.
Plug in 39 for m, 4.18 for C (the specific heat capacity of water), and 12 (which is 21 - 9) for change in T.
Multiply these numbers to get your answer.
To calculate the amount of heat required to raise the temperature of a sample of water, you can use the formula:
Q = m * c * ΔT
where:
Q is the amount of heat,
m is the mass of the sample,
c is the specific heat capacity of water, and
ΔT is the change in temperature.
Given:
m = 39 g
ΔT = (21 °C - 9 °C) = 12 °C (change in temperature)
The specific heat capacity of water is approximately 4.18 J/g°C.
Using the formula, we can calculate the amount of heat required:
Q = 39 g * 4.18 J/g°C * 12 °C
Q = 1948.08 J
Therefore, the amount of heat required to raise the temperature of the 39 g sample of water from 9 °C to 21 °C is 1948.08 Joules.
To calculate the amount of heat required to raise the temperature of a sample of water, you can use the equation:
Q = m * C * ΔT
Where:
Q is the amount of heat in Joules (J),
m is the mass of the substance in grams (g),
C is the specific heat capacity of the substance in J/g⋅°C, and
ΔT is the change in temperature in degrees Celsius (°C).
In this case, you have the following values:
m = 39 g (mass of water)
C = 4.18 J/g⋅°C (specific heat capacity of water)
ΔT = (21 °C - 9 °C) = 12 °C (change in temperature)
Now, plug these values into the equation:
Q = 39 g * 4.18 J/g⋅°C * 12 °C
First, multiply the mass (39 g) by the specific heat capacity (4.18 J/g⋅°C):
Q = 1621.02 J/g * 12 °C
Finally, multiply the answer by the change in temperature (12 °C):
Q = 19452.24 J
Therefore, the amount of heat required to raise the temperature of a 39 g sample of water from 9 °C to 21 °C is 19452.24 Joules (J).