Suppose 25 children who weigh the same are playing a game of tug-of-war. Five children pull with 10 newtons of force, while ten children pull with 15 newtons of force in the opposite direction. How can one determine the net force on the rope?(1 point)%0D%0AResponses%0D%0A%0D%0AThe forces are in opposite directions, so the newtons can be subtracted.%0D%0AThe forces are in opposite directions, so the newtons can be subtracted.%0D%0A%0D%0AThe newtons are in the same direction, so the newtons can be multiplied.%0D%0AThe newtons are in the same direction, so the newtons can be multiplied.%0D%0A%0D%0AThe forces are in opposite directions, so the newtons can be divided.%0D%0AThe forces are in opposite directions, so the newtons can be divided.%0D%0A%0D%0AThe forces are in the same direction, so the newtons can be added.
The forces are in opposite directions, so the newtons can be subtracted.
The forces are in opposite directions, so the newtons can be subtracted.
To determine the net force on the rope, you need to consider the direction and magnitude of the forces being applied on the rope.
In this scenario, there are two groups of children pulling in opposite directions. The first group exerts a force of 10 newtons and the second group exerts a force of 15 newtons. Since they are pulling in opposite directions, you need to subtract the forces to find the net force.
To calculate the net force, subtract the force exerted by the second group from the force exerted by the first group:
Net Force = Force of First Group - Force of Second Group
= 10 newtons - 15 newtons
= -5 newtons
The negative sign indicates the direction of the force. In this case, the net force is -5 newtons, indicating that the force on the rope is in the direction opposite to the force exerted by the second group of children.