A 0.050-m-long wire is carrying a current of 2.0 A at right angles to a 0.15-T magnetic field. What is the magnitude of the force exerted by the magnetic field on the wire?
A. 0.015 N
B. 0.0037 N
C. 0.67 N
D. 6.0 N
It's A right? 0.05*2*0.15
yes.
Well, it looks like you have the right equation, but let me put a little spin on it for you. To find the force exerted by the magnetic field on the wire, you multiply the length of the wire by the current flowing through it and then by the strength of the magnetic field. So, let's calculate it together for a little magnetic rodeo!
0.050 m * 2.0 A * 0.15 T = 0.015 N.
And voila! The answer is indeed A. 0.015 N. Yeehaw! I hope that gives you a shocking amount of joy!
To determine the magnitude of the force exerted by the magnetic field on the wire, you can use the formula:
F = I * L * B * sin(theta)
where:
F is the force exerted by the magnetic field on the wire,
I is the current flowing through the wire,
L is the length of the wire,
B is the magnitude of the magnetic field, and
theta is the angle between the direction of the current and the magnetic field.
In this case, the current in the wire is 2.0 A, the length of the wire is 0.050 m, the magnetic field is 0.15 T, and the angle between the current and the magnetic field is 90 degrees (since they are at right angles).
Plugging in these values into the formula:
F = 2.0 A * 0.050 m * 0.15 T * sin(90 degrees)
sin(90 degrees) equals 1, so we can simplify the equation:
F = 2.0 A * 0.050 m * 0.15 T * 1
Calculating this:
F = 0.015 N
Therefore, the magnitude of the force exerted by the magnetic field on the wire is 0.015 N. So the correct answer is A. 0.015 N.
To find the magnitude of the force exerted by the magnetic field on the wire, you can use the formula:
Force (F) = Current (I) * Length (L) * Magnetic Field (B) * sine(theta)
In this case, the current (I) is 2.0 A, the length (L) is 0.050 m, the magnetic field (B) is 0.15 T, and the angle (theta) between the current and the magnetic field is 90 degrees (since the current is at right angles to the magnetic field).
So, plugging in the values:
F = 2.0 A * 0.050 m * 0.15 T * sin(90°)
Now, the sine of 90 degrees is 1. Therefore:
F = 2.0 A * 0.050 m * 0.15 T * 1
F = 0.015 N
Therefore, the magnitude of the force exerted by the magnetic field on the wire is 0.015 N.
So, the correct option is A. 0.015 N.