Sodium reacts with chlorine to form the compound sodium chloride, or salt. The chemical formula below shows how the two elements combine into a compound.
2Na + Cl2 → 2NaCl
If the total mass of the reactants is 58.44 amu, what will be the total mass of the products?
(1 point)
Responses
58.44 amu
58.44 amu
116.88 amu
116.88 amu
29.22 amu
29.22 amu
60 amu
The total mass of the products can be calculated by adding up the atomic masses of sodium and chlorine in the reactants and then multiplying by the stoichiometric coefficient of the product.
The atomic mass of sodium is 22.99 amu, and there are 2 moles of sodium in 2NaCl.
The atomic mass of chlorine is 35.45 amu, and there is 1 mole of chlorine in 2NaCl.
(2 mol Na) * (22.99 amu/mol Na) + (1 mol Cl2) * (35.45 amu/mol Cl2) = 2NaCl
(45.98 amu) + (35.45 amu) = 81.43 amu
Therefore, the total mass of the products is 81.43 amu.
To determine the total mass of the products, we need to calculate the molar mass of sodium chloride (NaCl). The molar mass of an element is the mass in grams of one mole of that element.
The molar mass of sodium (Na) is approximately 22.99 g/mol, and the molar mass of chlorine (Cl) is approximately 35.45 g/mol.
To find the molar mass of NaCl, we add the molar masses of Na and Cl:
Molar mass of NaCl = Molar mass of Na + Molar mass of Cl
= 22.99 g/mol + 35.45 g/mol
= 58.44 g/mol
Since the coefficients in the balanced equation represent the mole ratio between reactants and products, the total mass of the products will also be 58.44 amu.
Therefore, the correct answer is:
Total mass of the products = 58.44 amu.
To determine the total mass of the products, we need to calculate the molar mass of sodium (Na) and chlorine (Cl2), and then use the balanced chemical equation to understand the ratio between the reactants and products.
The molar mass of sodium (Na) is 22.99 g/mol, while the molar mass of chlorine (Cl2) is 35.45 g/mol.
In the balanced chemical equation 2Na + Cl2 → 2NaCl, we can see that for every 2 moles of sodium (Na) and 1 mole of chlorine (Cl2) that react, we get 2 moles of sodium chloride (NaCl) produced.
So, to determine the total mass of the products, we need to calculate the mass of sodium chloride (NaCl) produced. Since the molar mass of sodium chloride (NaCl) is 58.44 g/mol, we can multiply the number of moles of NaCl by its molar mass to get the mass.
In this case, because the balanced equation tells us that 2 moles of NaCl are produced for every 2 moles of Na and 1 mole of Cl2, the number of moles of NaCl formed will also be 2.
Therefore, the mass of the products will be:
2 moles (NaCl) × 58.44 g/mol (molar mass of NaCl) = 116.88 g
Hence, the total mass of the products will be 116.88 amu.
Sodium reacts with chlorine to form the compound sodium chloride, or salt. The chemical formula below shows how the two elements combine into a compound.
2Na + Cl2 → 2NaCl
If the total mass of the reactants is 58.44 amu, what will be the total mass of the products?
(1 point)
Responses
58.44 amu
58.44 amu
116.88 amu
116.88 amu
29.22 amu
29.22 amu
60 amu
The total mass of the products can be determined by calculating the molar mass of sodium chloride (NaCl) and using the stoichiometric coefficients from the balanced chemical equation.
The molar mass of sodium (Na) is approximately 22.99 g/mol, and the molar mass of chlorine (Cl2) is approximately 70.90 g/mol (35.45 g/mol x 2).
To find the molar mass of NaCl, we add the molar masses of Na and Cl:
Molar mass of NaCl = Molar mass of Na + Molar mass of Cl
= 22.99 g/mol + 70.90 g/mol
= 93.89 g/mol
Since 2 moles of NaCl are formed for every 2 moles of Na and 1 mole of Cl2, we know that the molar mass of NaCl is equal to the total mass of the products in grams.
Therefore, the total mass of the products is 93.89 g/mol.
However, the question asks for the total mass of the products in amu (atomic mass units) and not grams.
To convert grams to amu, we can use the conversion factor:
1 g/mol = 1 amu
So, the mass of the products in amu will still be equal to 93.89 amu.
Therefore, the correct answer is:
Total mass of the products = 93.89 amu.