Evaluate the following expression when x = 5: 8(2x+6)(1 point) Responses 86 86 24 24 104 104 128
To evaluate the expression when x = 5, we substitute x with 5 in the expression:
8(2(5) + 6)
This simplifies to:
8(10 + 6)
8(16)
And the final result is:
128
To evaluate the expression when x = 5, we substitute the value of x into the expression:
8(2x + 6)
Since x = 5:
8(2(5) + 6)
First, we simplify within the parentheses:
8(10 + 6)
Next, we simplify the addition within the parentheses:
8(16)
Finally, we multiply:
128
Therefore, the expression evaluates to 128 when x = 5.
To evaluate the expression when x = 5, we need to substitute the value of x into the expression and perform the calculations accordingly.
The given expression is: 8(2x + 6)
Substituting x = 5, we get: 8(2 * 5 + 6)
First, we need to evaluate what's inside the parentheses: 2 * 5 = 10
Next, we add the result to 6: 10 + 6 = 16
Now, we multiply 8 by the result: 8 * 16 = 128
Therefore, the value of the expression when x = 5 is 128.
Evaluate the following expression: 3x+6−y when x = 2 and y = 5(1 point) Responses 10 10 7 7 6 6 4
To evaluate the expression when x = 2 and y = 5, we substitute the values into the expression:
3x + 6 - y
Substituting x = 2 and y = 5, we get:
3(2) + 6 - 5
Multiplying:
6 + 6 - 5
Adding and subtracting:
12 - 5
7
Therefore, the value of the expression when x = 2 and y = 5 is 7.
Evaluate the following expression: 5c−2k when c = 7 and k = 3(1 point) Responses 7 7 29 29 3 3 34
To evaluate the expression when c = 7 and k = 3, we substitute the values into the expression:
5c - 2k
Substituting c = 7 and k = 3, we get:
5(7) - 2(3)
Multiplying:
35 - 6
Subtracting:
29
Therefore, the value of the expression when c = 7 and k = 3 is 29.
Evaluate the following expression: 2(k3+h−e) when h = 18, k = 2, and e = 7(1 point) Responses 34 34 19 19 38 38 98
To evaluate the expression when h = 18, k = 2, and e = 7, we substitute the values into the expression:
2(k^3 + h - e)
Substituting h = 18, k = 2, and e = 7, we get:
2(2^3 + 18 - 7)
Evaluating the exponent:
2(8 + 18 - 7)
Performing the addition and subtraction within the parentheses:
2(8 + 11)
Multiplying:
2(19)
And the final result is:
38
Therefore, the value of the expression when h = 18, k = 2, and e = 7 is 38.
Evaluate the following expression: 4c+72−r+2w when w = 3, c = 5, and r = 11(1 point) Responses 64 64 29 29 106 106 21
To evaluate the expression when w = 3, c = 5, and r = 11, we substitute the values into the expression:
4c + 72 - r + 2w
Substituting w = 3, c = 5, and r = 11, we get:
4(5) + 72 - 11 + 2(3)
Multiplying:
20 + 72 - 11 + 6
Performing the addition and subtraction:
92 - 11 + 6
75 + 6
81
Therefore, the value of the expression when w = 3, c = 5, and r = 11 is 81.
Evaluate the following expression: 4c+7 to the power of 2−r+2w when w = 3, c = 5, and r = 11(1 point) Responses 64 64 29 29 106 106 21
To evaluate the expression when w = 3, c = 5, and r = 11, we substitute the values into the expression:
4c + 7^2 - r + 2w
Substituting w = 3, c = 5, and r = 11, we get:
4(5) + 7^2 - 11 + 2(3)
Multiplying:
20 + 49 - 11 + 6
Performing the addition and subtraction:
69 - 11 + 6
58 + 6
64
Therefore, the value of the expression when w = 3, c = 5, and r = 11 is 64.
A soccer game is 90 minutes with m minutes of stoppage time. The total time is 90 + m. How long is the game with 23 minutes stoppage time?(1 point) Responses 102 minutes 102 minutes 113 minutes 113 minutes 78 minutes 78 minutes 67 minutes
To find the total time of the game with 23 minutes of stoppage time, we need to add the stoppage time to the 90-minute game.
Total time = 90 + stoppage time
Substituting stoppage time = 23, we get:
Total time = 90 + 23
Total time = 113 minutes
Therefore, the game with 23 minutes of stoppage time will last for 113 minutes.
Marri bought 1/2 pound of licorice, 1/3 pound of candy worms, and 2/5 pound of jawbreakers. How many more pounds of licorice than candy worms did she buy?(1 point)
To find the difference in pounds between the licorice and candy worms, subtract the weight of the candy worms from the weight of the licorice.
Licorice - Candy worms = 1/2 - 1/3
To subtract fractions, we need to find a common denominator. In this case, the least common denominator (LCD) is 6.
1/2 = 3/6
1/3 = 2/6
Now, we can subtract:
3/6 - 2/6 = 1/6
Therefore, Marri bought 1/6 more pounds of licorice than candy worms.
Jn Trial. The first day they hiked 4 1/6 miles and the second day they hiked 3 2/3 miles. What total distance diames and Luke took a two-day hike along the Appalachiad the boys hike?(1 point)
To find the total distance Jacob and Luke hiked for the two-day hike, we need to add the distances they hiked on each day.
First day: 4 1/6 miles
Second day: 3 2/3 miles
To add these fractions, we need to find a common denominator. In this case, the least common denominator (LCD) is 6.
1/6 can be written as 1/6 * 6/6 = 6/36
2/3 can be written as 2/3 * 6/6 = 12/36
Now, we can add the fractions:
4 1/6 + 3 2/3 = 4 + 1/6 + 3 + 2/3
In whole numbers:
4 + 3 = 7
Adding the fractions:
1/6 + 2/3 = 6/36 + 12/36 = 18/36 = 1/2
Combining the whole number and fraction:
7 1/2
Therefore, Jacob and Luke hiked a total distance of 7 1/2 miles for the two-day hike along the Appalachian Trail.
Jiani gets paid for a job every 9 weeks and Rosa gets paid for a job every 12 weeks. How many weeks will it take for them to get paid at the same time? Type your response into the box below.(1 point)
To find the number of weeks it will take for Jiani and Rosa to get paid at the same time, we need to find the least common multiple (LCM) of 9 and 12.
The prime factorization of 9 is 3 * 3 = 3^2.
The prime factorization of 12 is 2 * 2 * 3 = 2^2 * 3.
The LCM is the product of the highest powers of all the prime factors:
LCM = 2^2 * 3^2 = 4 * 9
LCM = 36
Therefore, it will take 36 weeks for Jiani and Rosa to get paid at the same time.