Two forces act on an object. One force has a magnitude of 30N directed west, and the other force has a magnitude of 12 N directed east. What is the net force on the object?
42N west
42 N east
18N west
18N east
The net force on the object is the vector sum of the two forces. Since one force is directed west and the other force is directed east, they have opposite directions.
To find the net force, we need to subtract the magnitude of the force directed east from the magnitude of the force directed west.
Magnitude of force directed west = 30N
Magnitude of force directed east = 12N
Net force = 30N - 12N = 18N
Therefore, the net force on the object is 18N west.
To find the net force on the object, we have to take into account the magnitudes and directions of the forces. If a force is in the west direction, we assign it a negative sign, and if a force is in the east direction, we assign it a positive sign.
So, we have a force of 30N directed west and a force of 12 N directed east.
To calculate the net force, we subtract the force directed east from the force directed west:
Net force = Magnitude of force west - Magnitude of force east
Net force = 30N - 12N
Net force = 18N west
Therefore, the net force on the object is 18N west.
To find the net force on the object, you need to consider the direction and magnitude of the forces acting on it.
In this case, you have one force with a magnitude of 30N directed west and another force with a magnitude of 12N directed east. When forces act in opposite directions, as they do here, you subtract the smaller force from the larger force.
So, to find the net force, subtract 12N (the smaller force) from 30N (the larger force):
30N - 12N = 18N
Therefore, the net force on the object is 18N. However, we need to consider the direction as well.
Since the larger force is directed west and the smaller force is directed east, the net force is in the direction of the larger force, which is west.
Therefore, the correct answer is 18N west.