Two forces act on an object. One force has a magnitude of 10 N directed north, and the other force has a magnitude of 2 N directed south. What is the net force on the object?(1 point)%0D%0AResponses%0D%0A%0D%0A25 N north%0D%0A25 N north%0D%0A%0D%0A8 N north%0D%0A8 N north%0D%0A%0D%0A8 N south%0D%0A8 N south%0D%0A%0D%0A12 N south
To find the net force, we need to subtract the force directed south from the force directed north.
Magnitude of the force directed north: 10 N
Magnitude of the force directed south: 2 N
Net force = 10 N - 2 N = 8 N
So, the net force on the object is 8 N north.
To find the net force on an object, we need to consider both the magnitude and direction of the forces acting on it. In this case, we have:
- One force with a magnitude of 10 N directed north
- Another force with a magnitude of 2 N directed south
Since these forces act in opposite directions, we can subtract the magnitude of the force directed south from the magnitude of the force directed north:
10 N - 2 N = 8 N
So, the net force on the object is 8 N. However, we also need to consider the direction of the net force. Since the force directed north is greater in magnitude, the net force will be directed northward as well.
Therefore, the correct answer is 8 N north.
To find the net force on an object, you need to calculate the sum of all the forces acting on it. In this case, one force has a magnitude of 10 N directed north, and the other force has a magnitude of 2 N directed south.
To calculate the net force, you can subtract the force directed south from the force directed north since they are acting in opposite directions.
10 N (north) - 2 N (south) = 8 N (north)
Therefore, the net force on the object is 8 N directed north.