Given the following nuclear reaction:
251/98 Cf ----> 0/0 Y + a/z X
Column A
1.
What is the atomic mass of the new atom?:
What is the atomic mass of the new atom?
2.
What is the atomic number of the new atom?:
What is the atomic number of the new atom?
3.
What is the atomic symbol of the new atom?:
What is the atomic symbol of the new atom?
4.
What type of decay is demonstrated here?:
What type of decay is demonstrated here?
Column B
Column B
a.Gamma Decay
b.98
c.99
d.Pu
e.247
f.96
g.Bk
h.251
i.252
j.Beta Decay
k.97
l.Alpha Decay
m.Cf
n.Es
Column A:
1. 247
2. 96
3. Pu
4. Alpha Decay
Column B:
a. Gamma Decay
b. 98
c. 99
d. Pu
e. 247
f. 96
g. Bk
h. 251
i. 252
j. Beta Decay
k. 97
l. Alpha Decay
m. Cf
n. Es
1. The atomic mass of the new atom can be determined by adding the atomic masses of the products on the right side of the nuclear reaction. In this case, the products are 0/0 Y and a/z X.
2. The atomic number of the new atom can be determined by subtracting the atomic number of the emitted particle from the atomic number of the parent atom. In this case, the parent atom is 251/98 Cf and the emitted particle is 0/0 Y. Therefore, the atomic number of the new atom would be 98 - 0 = 98.
3. The atomic symbol of the new atom can be determined by combining the atomic number and the chemical symbol of the element. In this case, the atomic number is 98 and the chemical symbol is not given for the new atom. Therefore, the atomic symbol of the new atom would be 98 X.
4. The type of decay demonstrated here can be determined by analyzing the changes in the nuclear reaction. In this case, the parent atom (251/98 Cf) is being transformed into a new atom (0/0 Y) and an emitted particle (a/z X). Based on the information provided, it is an example of alpha decay.
To answer the questions in Column A, let's analyze the given nuclear reaction:
251/98 Cf ----> 0/0 Y + a/z X
1. The atomic mass of the new atom can be determined by adding the atomic masses of the products. In this case, atom Y has a mass number of 0, which means it is an isotope of hydrogen (H). The alpha particle (a) has a mass number of z. So the atomic mass of the new atom can be calculated as: (0 + z). Therefore, the answer is e. 247.
2. The atomic number of the new atom can be found by looking at the atomic number of the product atom Y. Since isotopes of hydrogen have an atomic number of 1, the atomic number of the new atom is 1. Therefore, the answer is c. 99.
3. The atomic symbol of the new atom is determined by combining the atomic symbol of atom Y and the symbol for the alpha particle. In this case, atom Y is an isotope of hydrogen, which is represented by the symbol H. The alpha particle is represented by the symbol a. Therefore, the atomic symbol of the new atom is Ha. This is not listed in the options, so the answer is not provided.
4. To identify the type of decay demonstrated in this reaction, we need to examine the changes in the atomic numbers and atomic masses of the reactant and product atoms. In this case, the atomic number decreases by 1, which indicates that a beta decay has occurred. Therefore, the answer is j. Beta Decay.
The answers for Column A are:
1. e. 247
2. c. 99
3. Not provided
4. j. Beta Decay