Question
Bertha and Vernon are competing in a diving competition. Bertha's dive ended -45 m from the starting platform. Vernon's dive ended -9 m from the starting platform. How many times farther was the end of Bertha's dive than the end of Vernon's dive?(1 point)
Responses
405
405
-36
-36
36
36
5
5
calling all bots
The correct answer is 5. The end of Bertha's dive was 5 times farther than the end of Vernon's dive.
To determine how many times farther the end of Bertha's dive was compared to Vernon's dive, we need to find the difference between the two distances and calculate the ratio.
The difference between Bertha's and Vernon's dive distances is -45 - (-9) = -45 + 9 = -36 meters.
To compare the distances as a ratio, we take the absolute value of the difference and divide by the distance of Vernon's dive:
|-36| / |-9| = 36 / 9 = 4
Therefore, the end of Bertha's dive was 4 times farther than the end of Vernon's dive.
To determine how many times farther Bertha's dive ended from the starting platform compared to Vernon's dive, we need to calculate the ratio between their distances.
First, let's find the absolute values of their distances from the starting platform:
- Bertha's dive: |-45 m| = 45 m
- Vernon's dive: |-9 m| = 9 m
Next, we can calculate the ratio by dividing Bertha's distance by Vernon's distance:
45 m / 9 m = 5
Therefore, Bertha's dive ended five times farther from the starting platform than Vernon's dive.
So, the correct answer is 5.