Maria has to spend 5 1/2 hours to finish her community service program in a community health clinic. Last week, she was able to spend 3 3/4 hours. Which equation can be used to determine the number of hours, h , that Maria still needs to spend to complete her service program?(1 point)

Responses

h + 3 3/4 = 5 1/2
h plus 3 and three-fourths equals 5 and one-half

h + 5 1/2 = 3 3/4
h plus 5 and one-half equals 3 and three-fourths

h − 5 1/2 = 3 3/4
h minus 5 and one-half equals 3 and three-fourths

h − 3 3/4 = 5 1/2

a b c or d

The equation that can be used to determine the number of hours, h , that Maria still needs to spend to complete her service program is h - 3 3/4 = 5 1/2.

The correct equation that can be used to determine the number of hours Maria still needs to spend to complete her service program is:

h = 5 1/2 - 3 3/4

The equation that can be used to determine the number of hours Maria still needs to spend to complete her service program is:

h = 5 1/2 - 3 3/4

Explanation:
In the given problem, Maria needs to spend a total of 5 1/2 hours to complete her community service program. However, last week, she already spent 3 3/4 hours. To find out how many more hours she needs to spend, we subtract the hours she has already spent from the total hours needed.

So, we subtract 3 3/4 from 5 1/2:

5 1/2 - 3 3/4 = (11/2) - (15/4)

To perform this subtraction, we need to have a common denominator, which in this case is 4. We can convert 5 1/2 to the fraction (11/2) by multiplying the whole number (5) by the denominator of the fraction (2) and adding the numerator (1). This gives us:

(11/2) - (15/4)

Now that we have the same denominator (2 and 4) for both fractions, we can subtract the numerators:

(11/2) - (15/4) = (22/4) - (15/4)

Subtracting the numerators gives us:

(22/4) - (15/4) = 7/4

Therefore, the equation to determine the number of hours Maria still needs to spend is:

h = 7/4 or h = 1 3/4

However, none of the given options match this equation. So, the correct choice is not provided in the given responses.