Claire works two jobs; she works 54 hours in one week with these two jobs and makes $10 an hour. She is trying to save up for a trip that cost her $5000. She has set aside $1500 already. Write an inequality to represent the minimum amount of weeks she needs to work to save at least 5000. (1 point)
Responses
54(10)x+1500≥5000
54 10 x plus 1500 is greater than or equal to 5000
54(10)x−1500≤5000
54 10 x minus 1500 is less than or equal to 5000
10x+1500≥5000
10 x plus 1500 is greater than or equal to 5000
10x+1500≤5000
10 x plus 1500 is less than or equal to 5000
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10x + 1500 ≥ 5000
10x + 1500 ≥ 5000
To solve this problem, we need to consider Claire's earnings and how much she needs to save.
We know that Claire works 54 hours in one week with these two jobs and earns $10 per hour. Therefore, her total earnings in one week can be calculated as 54 * 10 = $540.
Let's assume Claire needs to work x weeks to save at least $5000.
To find the minimum amount of weeks she needs to work, we can set up an inequality.
Since she has already set aside $1500, her total earnings after x weeks of work will be 540x + 1500.
This total earnings should be greater than or equal to $5000, so the inequality can be written as:
540x + 1500 ≥ 5000
Therefore, the correct inequality to represent the minimum amount of weeks she needs to work to save at least $5000 is:
54 * 10 * x + 1500 ≥ 5000.
So the correct option is: 54(10)x+1500≥5000.