A fire engines water tank holds 750 gallons of water if the pump removes 250 gallons of water in 5 minutes what is the charge in the amount of water in gallons in 1 minute
The charge in the amount of water in gallons in 1 minute is equal to the amount of water removed in 5 minutes divided by 5.
In this case, the amount of water removed in 5 minutes is 250 gallons, so the charge in the amount of water in 1 minute is 250/5 = <<250/5=50>>50 gallons. Answer: \boxed{50}.
To find the change in the amount of water in 1 minute, we need to determine the rate at which the pump removes water.
Given that the pump removes 250 gallons of water in 5 minutes, we can calculate the rate of removal per minute by dividing the amount removed by the time:
Rate of removal = 250 gallons / 5 minutes
= 50 gallons/minute
Therefore, the rate at which the pump removes water is 50 gallons per minute.
To find the change in the amount of water in 1 minute, we need to determine how much water is being removed per minute.
Given that the pump removes 250 gallons of water in 5 minutes, we can calculate the amount of water being removed per minute.
First, we can find the amount of water being removed per minute by dividing 250 gallons by 5 minutes:
Amount of water removed per minute = 250 gallons / 5 minutes = 50 gallons/minute
Therefore, the change in the amount of water in 1 minute is 50 gallons.