A fire engine water tank holds 750 gallons of water if the pump removes 250 of water in 5 minutes what is the change in the amount of water in gallons in one minute
To find the change in the amount of water in one minute, divide the amount of water removed in 5 minutes by 5.
250 gallons / 5 minutes = <<250/5=50>>50 gallons/minute.
Therefore, the change in the amount of water in one minute is 50 gallons.
Is it negative or positive
The change in the amount of water in one minute is a decrease of 50 gallons. It is typically represented as a negative number, so in this case, it would be -50 gallons/minute.
Is it -50 or -15
Apologies for the confusion in my previous response. Let's update the calculation.
If 250 gallons of water are removed in 5 minutes, the change in the amount of water in one minute can be calculated as:
250 gallons / 5 minutes = 50 gallons/minute.
Thus, the change in the amount of water in one minute would be a decrease of 50 gallons. Therefore, the correct answer is -50 gallons/minute.
To calculate the change in the amount of water in one minute, we need to find the rate at which water is being removed from the tank.
Given:
Water tank capacity = 750 gallons
Water removal rate = 250 gallons in 5 minutes
To find the rate in one minute, we can divide the water removed in 5 minutes by 5:
250 gallons / 5 minutes = 50 gallons/minute
Therefore, the change in the amount of water in one minute is 50 gallons.
To find the change in the amount of water in one minute, we need to determine the amount of water that the pump removes in one minute.
We know that the pump removes 250 gallons of water in 5 minutes.
To find out how much water is pumped in one minute, we need to divide 250 gallons by 5 minutes:
250 gallons / 5 minutes = 50 gallons/minute
Therefore, the pump removes 50 gallons of water in one minute.