How many even numbers can be formed from the digits 1, 2, 3, 4, 5?

To form an even number, the last digit must be even. Therefore, we can choose the last digit in $2$ ways (either 2 or 4). The remaining four digits can be arranged in $4!$ ways. Thus, there are $2\cdot 4! = \boxed{48}$ even numbers that can be formed from the digits 1, 2, 3, 4, 5.

To determine how many even numbers can be formed from the digits 1, 2, 3, 4, and 5, let's go through the steps:

Step 1: Count the number of available options for the units place. Since we are looking for even numbers, the units place should have one of the even digits: 2, 4 or if the digit is used only once

Step 2: Count the number of available options for the tens place. Since we can use any of the remaining digits (except 0, as it would create a number with leading zeros), there are four remaining options: 1, 3, 4, and 5.

Step 3: Multiply the number of options for each place together. In this case, there is 1 option for the units place (2 or 4) and 4 options for the tens place (1, 3, 4, or 5). Therefore, the total number of even numbers that can be formed is 1 * 4 = 4.

So, there are 4 even numbers that can be formed from the digits 1, 2, 3, 4, and 5.

To find the number of even numbers that can be formed from the digits 1, 2, 3, 4, 5, we need to determine the total number of possibilities and then filter out the odd numbers.

We have 5 digits to choose from (1, 2, 3, 4, 5), and we need to form a number from these digits. The first digit of an even number must be one of the even digits (2 or 4). So, we have 2 choices for the first digit.

After choosing the first digit, we have 4 remaining digits to choose from for the second digit. However, any digit can be repeated in the remaining positions, so we have 5 choices for each of the remaining three digits.

Therefore, the total number of even numbers that can be formed is calculated as follows:

Number of even numbers = 2 (choices for the first digit) * 5 (choices for each of the remaining three digits) * 5 * 5 = 250

Therefore, there are 250 even numbers that can be formed from the digits 1, 2, 3, 4, 5.