determine the sum of all the numbers that can be formed with the digits 1,2 and 3, each digit occurring only once in a number?
there is no question in related question so please tell me the answer of my question.
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answer in my book is 1332 and your answer is 1470 if i add all digits
i got 1332 thank u
To determine the sum of all the numbers that can be formed with the digits 1, 2, and 3, each occurring only once in a number, we can use a permutation approach.
First, let's list down all the possible combinations of the given digits:
1, 2, 3
1, 3, 2
2, 1, 3
2, 3, 1
3, 1, 2
3, 2, 1
Now, to find the sum of these numbers, we need to add them all up.
1 + 2 + 3 = 6
1 + 3 + 2 = 6
2 + 1 + 3 = 6
2 + 3 + 1 = 6
3 + 1 + 2 = 6
3 + 2 + 1 = 6
Each combination results in a sum of 6. Since there are six combinations, we can simply multiply 6 by 6 to get the total sum:
6 x 6 = 36
Therefore, the sum of all the numbers that can be formed with digits 1, 2, and 3, each occurring only once, is 36.