Which correctly shows the area formula for a trapezoid, A=1/2h(b1+b2) , rearranged for the quantity of interest h?
h=12A(b1+b2) h equals Start Fraction 1 over 2 End Fraction upper A left parenthesis b subscript 1 baseline plus b subscript 2 baseline right parenthesis b1=2Ah−b2 b subscript 1 baseline dequals Start Fraction 2 upper A over h End Fraction minus b subscript 2 baseline h=b1+b22A h equals Start Fraction b subscript 1 baseline plus b subscript 2 baseline over 2 upper A End Fraction h=2Ab1+b2 h equals Start Fraction 2 upper A over b subscript 1 baseline plus b subscript 2 baseline End Fraction
h = 2A / (b1 + b2)
The correct rearranged formula for the quantity of interest "h" is:
h = 2A / (b1 + b2)
The correct rearranged formula for the quantity of interest h in the area formula for a trapezoid is:
h = (2A) / (b1 + b2)
Here's an explanation:
Starting with the original formula: A = (1/2)h(b1 + b2)
To rearrange it for h, we need to isolate h on one side of the equation.
1. First, multiply both sides of the equation by 2 to cancel out the fraction:
2A = h(b1 + b2)
2. Now, divide both sides of the equation by (b1 + b2) to solve for h:
h = (2A) / (b1 + b2)
So, h equals (2A) divided by (b1 + b2).
The correct rearranged formula for h in terms of A, b1, and b2 is h = (2A) / (b1 + b2).