Find the value of AB base 12 - 45 base 12
To calculate the value of AB base 12 - 45 base 12, we need to perform the subtraction in base 12.
First, let's list the digits in base 12:
0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B.
Since B is the highest digit in base 12, we need to borrow from the left in the subtraction. We can't subtract 5 from B, so we borrow from the A digit, making it A - 1 = 10 - 1 = 9.
Now, the subtraction becomes:
A - 1 B base 12
- 4 5 base 12
Let's subtract each digit:
A - 4 = 10 - 4 = 6
9 - 5 = 9 - 5 = 4
Therefore, AB base 12 - 45 base 12 is equal to 64 base 12.
To find the value of AB base 12 - 45 base 12, convert both numbers to base 10 and then subtract them.
First, let's convert AB base 12 to base 10.
In base 12, A represents 10 and B represents 11. Therefore, AB base 12 can be written as 10 * 12^1 + 11 * 12^0.
Calculating the value:
AB base 12 = 10 * 12^1 + 11 * 12^0
= 120 + 11
= 131
Now, let's convert 45 base 12 to base 10.
In base 12, 4 represents 4 and 5 represents 5. Therefore, 45 base 12 can be written as 4 * 12^1 + 5 * 12^0.
Calculating the value:
45 base 12 = 4 * 12^1 + 5 * 12^0
= 48 + 5
= 53
Now, subtract the values:
131 - 53 = 78
Therefore, AB base 12 - 45 base 12 is equal to 78 base 10.
To find the value of AB base 12 - 45 base 12, we need to subtract these two numbers in base 12.
In base 12, we have the digits 0-9 followed by A and B, representing 10 and 11 respectively.
To subtract these numbers, we start from the rightmost digit and work our way left, borrowing when necessary.
Let's start by subtracting the ones place:
B (11 base 12)
- 5 (5 base 12)
Since 11 base 12 is greater than 5 base 12, we can subtract directly:
B (11 base 12) - 5 (5 base 12) = 6 (6 base 12).
Now let's move to the twelves place:
A (10 base 12)
- 4 (4 base 12)
Again, 10 base 12 is greater than 4 base 12, so we can subtract directly:
A (10 base 12) - 4 (4 base 12) = 6 (6 base 12).
Therefore, AB base 12 - 45 base 12 = 66 base 12.