Sodium reacts with chlorine to form the compound sodium chloride, or salt. The chemical formula below shows how the two elements combine into a compound.
2Na + Cl2 -- 2NaCl
If the total mass of the reactants is 58.44 amu, what will be the total mass of the products?
1. 60 amu
2. 116.88 amu
3. 58.44 amu
4. 29.22 amu
The chemical equation provided shows that 2 moles of sodium (2Na) react with 1 mole of chlorine (Cl2) to form 2 moles of sodium chloride (2NaCl).
To calculate the total mass of the products, we need to determine the molar mass of sodium chloride (NaCl).
Sodium (Na) has a molar mass of 22.99 g/mol, and chlorine (Cl) has a molar mass of 35.45 g/mol.
Molar mass of NaCl = (molar mass of Na) + (molar mass of Cl)
= 22.99 g/mol + 35.45 g/mol
= 58.44 g/mol
Given that the total mass of the reactants is 58.44 amu, it means that the total mass of the products will be the same.
Therefore, the correct answer is option 3. 58.44 amu.
To determine the total mass of the products, we need to calculate the molar masses of the reactants and use the stoichiometric coefficients of the balanced equation.
The molar mass of sodium (Na) is 22.99 g/mol, and the molar mass of chlorine (Cl2) is 35.45 g/mol (since chlorine exists as a diatomic molecule).
The molar mass of sodium chloride (NaCl) is the sum of the molar masses of sodium and chlorine, which is 58.44 g/mol (22.99 g/mol + 35.45 g/mol).
Since the stoichiometric coefficient for sodium (Na) in the balanced equation is 2, we need to multiply the molar mass of sodium chloride by 2 to calculate the total mass of the products.
Total mass of the products = 2 * 58.44 g/mol = 116.88 g/mol
Therefore, the total mass of the products will be 116.88 amu.
Option 2, 116.88 amu, is the correct answer.
To find the total mass of the products, we need to calculate the total mass of sodium chloride (NaCl).
First, let's calculate the molar mass of sodium chloride (NaCl). The molar mass of sodium (Na) is 22.99 g/mol, and the molar mass of chlorine (Cl) is 35.45 g/mol.
The molar mass of sodium chloride (NaCl) is:
(2 x molar mass of sodium) + (1 x molar mass of chlorine)
= (2 x 22.99 g/mol) + (1 x 35.45 g/mol)
= 45.98 g/mol + 35.45 g/mol
= 81.43 g/mol
Now, let's calculate the number of moles of sodium chloride (NaCl) that will be formed. Since the balanced equation shows that 2 moles of sodium (Na) react with 1 mole of chlorine (Cl2) to form 2 moles of sodium chloride (2NaCl), we can determine that the number of moles of sodium chloride formed is equal to the number of moles of sodium (Na) used.
Given that the total mass of the reactants is 58.44 amu, which represents the total mass of sodium (Na) used, we can convert this mass to moles using the molar mass of sodium (Na).
Number of moles of sodium chloride (NaCl) = mass of sodium (Na) used / molar mass of sodium (Na)
= 58.44 g / 22.99 g/mol
= 2.54 mol
Since 2 moles of sodium chloride (2NaCl) are formed for every 2 moles of sodium (Na) used, we can determine that the total mass of the products will be equal to the molar mass of sodium chloride (NaCl) multiplied by the number of moles of sodium chloride formed.
Total mass of the products = molar mass of sodium chloride (NaCl) x number of moles of sodium chloride formed
= 81.43 g/mol x 2.54 mol
= 206.81 g
Therefore, the total mass of the products will be approximately 206.81 g.
None of the provided answer choices match the calculated value.