A fire engine's water tank holds 750 gallons of water. If the pump removes 250 gallons of water in 5 minutes. What is the change in the amount of water in gallons in 1 minute?
A. -50
B. 15
C. 50
D. -15
To find the change in the amount of water in 1 minute, we need to find the rate at which the pump removes water in 1 minute.
The rate at which the pump removes water is 250 gallons per 5 minutes.
To find the rate at which the pump removes water in 1 minute, we divide 250 gallons by 5 minutes:
250 gallons / 5 minutes = 50 gallons per minute.
Therefore, the change in the amount of water in 1 minute is 50 gallons.
The answer is C. 50.
To find the change in the amount of water in 1 minute, we need to determine the rate at which water is being removed.
The pump removes 250 gallons of water in 5 minutes, so we can set up a proportion:
250 gallons / 5 minutes = x gallons / 1 minute
To solve for x, we can cross-multiply:
5 * x = 250 * 1
5x = 250
x = 250 / 5
x = 50
Therefore, the change in the amount of water in gallons in 1 minute is 50 gallons.
So, the correct answer is C. 50.
To find the change in the amount of water in 1 minute, we need to divide the change in the amount of water (250 gallons) by the time taken (5 minutes). Let's perform the calculation:
Change in water per minute = Change in water / Time taken
Change in water per minute = 250 gallons / 5 minutes
Change in water per minute = 50 gallons
Therefore, the change in the amount of water in 1 minute is 50 gallons. So, the correct answer is C. 50.