A membership at Gym A costs $50 for 5 months. A membership at Gym B down the street costs $40 for 3 months. You write two equations in the form of y=kx to try and figure out which membership would be cheaper for a year. What is the value of k for the cheaper membership?(1 point)

For Gym A, the equation is y = 50/5 * x = 10x.

For Gym B, the equation is y = 40/3 * x = 13.33x (rounded).

Since the value of k for Gym A is smaller (10 < 13.33), the value of k for the cheaper membership is 10. Answer: \boxed{10}.

To find the value of k for the cheaper membership, let's write the equations for both memberships:

For Gym A:
y = kx
y = 50x (where y represents the cost and x represents the number of months)

For Gym B:
y = kx
y = 40x (where y represents the cost and x represents the number of months)

To figure out the cheaper membership for a year, we need to compare the costs for 12 months.

For Gym A:
y = 50x
y = 50(12)
y = 600

For Gym B:
y = 40x
y = 40(12)
y = 480

Comparing the costs, we see that Gym B is cheaper for a year as the cost is $480, compared to Gym A's cost of $600.

Therefore, for the cheaper membership, the value of k is 40.

To find the value of k for the cheaper membership, we need to analyze the cost per month for each membership.

For Gym A:
The cost is $50 for 5 months.
So the cost per month is 50/5 = $10.
Therefore, the equation in the form of y = kx for Gym A would be y = 10x.

For Gym B:
The cost is $40 for 3 months.
So the cost per month is 40/3 = $13.33 (rounded to two decimal places).
Therefore, the equation in the form of y = kx for Gym B would be y = 13.33x.

Now, we need to compare the values of k for both equations to find the cheaper option.

In the equation y = kx, k represents the cost per unit or the slope of the line. The smaller the value of k, the cheaper the membership per month.

For Gym A: k = 10.
For Gym B: k = 13.33.

Comparing these two values, we can see that k = 10 is smaller than k = 13.33. Therefore, the membership at Gym A is cheaper.

Thus, the value of k for the cheaper membership is 10.

Two equations are written to express how far a car can go when driving on different roads. On Road 1, the car can go 60 miles in 2 hours. On Road 2, the car can go 90 miles in 4 hours. Write an equation where y is the distance in miles and x is the time in hours to represent the motion of the faster car.(1 point)