A membership at Gym A costs $50 for 5 months. A membership at Gym B down the street costs $40 for 3 months. You write two equations in the form of y=kx to try and figure out which membership would be cheaper for a year. What is the value of k for the cheaper membership?(1 point)
UNIT 4 L13 MATH 7 CONNECTIONS ACADEMY
1. Graph 2 shows a lower unit cost
2. The rate of the graph is -1.5
3. 0.75$ per marker
4. The value of k = 10
5. y=30x
Correct answer for that last one is y = 30x. The others are right.
ANONYMOUS IS CORRECT!! 5/5 100% TYSMM
Two equations are written to express how far a car can go when driving on different roads. On Road 1, the car can go 60 miles in 2 hours. On Road 2, the car can go 90 miles in 4 hours. Write an equation where y
is the distance in miles and x is the time in hours to represent the motion of the faster car.
To represent the motion of the faster car, we need to determine which road allows the car to travel more distance in less time. In this case, Road 2 allows the car to travel more distance in the same amount of time as Road 1.
On Road 1, the car can travel 60 miles in 2 hours, which can be expressed as y = (60/2)x.
On Road 2, the car can travel 90 miles in 4 hours, which can be expressed as y = (90/4)x.
Therefore, the equation representing the motion of the faster car is y = (90/4)x.
can you write it again but dont put the numbers in fraction form
Certainly! Here is the equation representing the motion of the faster car without using fractions:
On Road 1, the car can travel 60 miles in 2 hours, which can be expressed as y = 30x.
On Road 2, the car can travel 90 miles in 4 hours, which can be expressed as y = 22.5x.
Therefore, the equation representing the motion of the faster car is y = 22.5x.
Write an equation where y
is the distance in miles and x is the time in hours to represent the motion of the faster car.
To represent the motion of the faster car, we need to compare the speed at which it covers the distance for both roads. Since the car covers more distance in less time on Road 2, we will use the information from Road 2 to write the equation.
On Road 2, the car can go 90 miles in 4 hours. We can express this relationship as a rate: y = (90/4)x.
Therefore, the equation representing the motion of the faster car is y = 22.5x.