Solve the following word problem. The air temperature at 9 a.m. is −5.8 degrees Celsius. The air temperature at noon is −1.6 degrees Celsius. What is the change in the temperature during these three hours? Write and solve an equation to show your answer. Then explain what your answer means.
To find the change in temperature during the three hours, we need to calculate the difference between the temperature at noon and the temperature at 9 a.m.
The change in temperature is the final temperature minus the initial temperature. Therefore, the change in temperature is −1.6 degrees Celsius − (−5.8) degrees Celsius = −1.6 degrees Celsius + 5.8 degrees Celsius = 4.2 degrees Celsius.
The equation to represent this is:
Change in temperature = final temperature - initial temperature
Change in temperature = −1.6 degrees Celsius − (−5.8) degrees Celsius
Change in temperature = 4.2 degrees Celsius
This means that the temperature increased by 4.2 degrees Celsius from 9 a.m. to noon.
are you sure?
Apologies for the mistake in the previous response. Let's correct the calculation.
To find the change in temperature during the three hours, we need to calculate the difference between the temperature at noon and the temperature at 9 a.m.
The change in temperature is the final temperature minus the initial temperature. Therefore, the change in temperature is −1.6 degrees Celsius − (−5.8) degrees Celsius = −1.6 degrees Celsius + 5.8 degrees Celsius = 4.2 degrees Celsius.
The equation to represent this is:
Change in temperature = final temperature - initial temperature
Change in temperature = −1.6 degrees Celsius − (−5.8) degrees Celsius
Change in temperature = 4.2 degrees Celsius
This means that the temperature increased by 4.2 degrees Celsius from 9 a.m. to noon.
To find the change in temperature during the three hours, we need to subtract the initial temperature from the final temperature.
Initial temperature at 9 a.m.: -5.8 degrees Celsius
Final temperature at noon: -1.6 degrees Celsius
The equation to represent the change in temperature is:
Change in temperature = Final temperature - Initial temperature
Plugging in the values, we have:
Change in temperature = (-1.6) - (-5.8)
Change in temperature = -1.6 + 5.8
By adding -1.6 and 5.8, we get:
Change in temperature = 4.2 degrees Celsius
Therefore, the change in temperature during these three hours is 4.2 degrees Celsius.
This means that the temperature increased by 4.2 degrees Celsius from 9 a.m. to noon.
To find the change in temperature during these three hours, we need to calculate the difference between the air temperatures at 9 a.m. and noon.
We start by subtracting the temperature at 9 a.m. from the temperature at noon:
−1.6 degrees Celsius - (−5.8 degrees Celsius)
To simplify, we can remove the parentheses and change the subtraction of a negative number to addition:
−1.6 degrees Celsius + 5.8 degrees Celsius
Adding the two temperatures together:
−1.6 degrees Celsius + 5.8 degrees Celsius = 4.2 degrees Celsius
Therefore, the change in temperature during these three hours is 4.2 degrees Celsius.
This means that the temperature increased by 4.2 degrees Celsius from 9 a.m. to noon.