Solve the following word problem. The air temperature at 9 a.m. is −5.8 degrees Celsius. The air temperature at noon is −1.6 degrees Celsius. What is the change in the temperature during these three hours? Write and solve an equation to show your answer. Then explain what your answer means.(4 points)
To find the change in temperature during these three hours, we need to subtract the initial temperature from the final temperature.
Let's call the initial temperature at 9 a.m. T1 and the final temperature at noon T2.
T1 = -5.8 degrees Celsius
T2 = -1.6 degrees Celsius
The change in temperature during these three hours is T2 - T1.
Change in temperature = (-1.6) - (-5.8)
Change in temperature = -1.6 + 5.8
Change in temperature = 4.2 degrees Celsius
The change in the temperature during these three hours is 4.2 degrees Celsius. This means that the temperature increased by 4.2 degrees Celsius between 9 a.m. and noon.
so whats the answer
shorten the answer
To find the change in temperature during these three hours, we need to subtract the temperature at 9 am from the temperature at noon. Let's denote the change in temperature as ΔT.
The temperature at 9 am is -5.8 degrees Celsius, and the temperature at noon is -1.6 degrees Celsius. Therefore, the equation for the change in temperature is:
ΔT = (-1.6) - (-5.8)
To simplify, we can rewrite the equation as:
ΔT = -1.6 + 5.8
Solving this equation, we get:
ΔT = 4.2
The change in temperature during these three hours is 4.2 degrees Celsius.
This means that the temperature has increased by 4.2 degrees Celsius from 9 am to noon.
To find the change in temperature during the three-hour period, we need to subtract the initial temperature at 9 a.m. from the temperature at noon.
First, we define the initial temperature as -5.8 degrees Celsius and the temperature at noon as -1.6 degrees Celsius.
To calculate the change in temperature, we can subtract the initial temperature from the final temperature:
Change in temperature = Final temperature - Initial temperature
Change in temperature = (-1.6) - (-5.8)
= -1.6 + 5.8
= 4.2
Therefore, the change in temperature during the three-hour period is 4.2 degrees Celsius.
This means that the temperature increased by 4.2 degrees Celsius from 9 a.m. to noon.