Given that f(x)=9x2−50
, apply the Remainder Theorem to find the remainder of (9x2−50)÷(x−73)
.(1 point)
Responses
−2033
negative Start Fraction 203 over 3 End Fraction
−1
negative 1
−29
negative 29
−50
To apply the Remainder Theorem, we substitute 73 for x in the expression 9x^2 - 50:
f(73) = 9(73)^2 - 50
= 9(5329) - 50
= 47961 - 50
= 47911
Therefore, the remainder is 47911.
To apply the Remainder Theorem, we need to find the value of f(73), which represents the remainder when f(x) is divided by (x - 73).
So, substituting x = 73 into f(x) = 9x^2 - 50:
f(73) = 9(73)^2 - 50 = 9(5329) - 50 = 47961 - 50 = 47911.
Therefore, the remainder when (9x^2 - 50) is divided by (x - 73) is 47911.
To apply the Remainder Theorem, we substitute the value of the divisor, which is (x - 73), into the original polynomial, which is f(x) = 9x^2 - 50.
So, we have:
f(73) = 9(73)^2 - 50
Now, we can simplify and calculate the remainder:
f(73) = 9(5329) - 50
= 47961 - 50
= 47911
Therefore, the remainder when 9x^2 - 50 is divided by (x - 73) is 47911.