Solve the system of equations.
x=6y−3
2x+7y=13 (1 point)
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To solve this system of equations, we can use the method of substitution.
First, let's solve the first equation for x in terms of y:
x = 6y - 3
Now, substitute this expression for x in the second equation:
2(6y - 3) + 7y = 13
Simplifying, we get:
12y - 6 + 7y = 13
Combining like terms, we have:
19y - 6 = 13
Add 6 to both sides:
19y = 19
Divide both sides by 19:
y = 1
Now that we know the value of y, we can substitute it back into the first equation to find x:
x = 6(1) - 3
x = 3
Therefore, the solution to the system of equations is (x, y) = (3, 1).
To solve the system of equations:
Rearrange the first equation to solve for x:
x = 6y - 3
Now substitute this value of x into the second equation:
2(6y - 3) + 7y = 13
Expand the equation:
12y - 6 + 7y = 13
Combine like terms:
19y - 6 = 13
Add 6 to both sides:
19y = 19
Divide by 19:
y = 1
Now substitute the value of y back into the first equation to solve for x:
x = 6(1) - 3
x = 6 - 3
x = 3
Therefore, the solution to the system of equations is x = 3 and y = 1.
To solve the system of equations, we'll use the method of substitution.
Step 1: Solve the first equation for x in terms of y.
x = 6y - 3
Step 2: Substitute x in the second equation with its equivalent expression from step 1.
2(6y - 3) + 7y = 13
Step 3: Simplify and solve for y.
12y - 6 + 7y = 13
Combine like terms: 19y - 6 = 13
Add 6 to both sides: 19y = 19
Divide both sides by 19: y = 1
Step 4: Substitute the found value of y back into the first equation to solve for x.
x = 6(1) - 3
x = 6 - 3
x = 3
Therefore, the solution to the system of equations is x = 3 and y = 1.
Solve the system of equations.
8x−3y= −22
y=10+4x (1 point)
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