Solve the system by substitution.
x, equals, 7, y
x=
7y
3, x, minus, y, equals, minus, 40
3x−y=
−40
We have the system of equations:
x = 7y
3x - y = -40
We can solve the first equation for x:
x = 7y
Now, substitute this value of x into the second equation:
3(7y) - y = -40
Simplifying, we get:
21y - y = -40
Combining like terms:
20y = -40
Divide both sides by 20:
y = -2
Now substitute this value of y back into the first equation to find x:
x = 7(-2)
x = -14
Therefore, the solution to the system of equations is x = -14 and y = -2.
To solve the given system of equations by substitution, we need to find the value of one variable in one equation and substitute it into the other equation.
Let's solve for x in the first equation:
x = 7y
Now, substitute this value of x into the second equation:
3x - y = -40
Replace x with 7y:
3(7y) - y = -40
Simplify:
21y - y = -40
Combine like terms:
20y = -40
Divide both sides by 20:
y = -2
Now that we have the value of y, substitute it back into the first equation:
x = 7(-2)
x = -14
Therefore, the solution to the system of equations is x = -14 and y = -2.
To solve the system by substitution, we need to isolate one variable in one of the equations and substitute it into the other equation. Let's start with the first equation:
x = 7y
Now, we can substitute this value of x into the second equation:
3x - y = -40
Substituting x = 7y:
3(7y) - y = -40
Simplifying:
21y - y = -40
Combining like terms:
20y = -40
Dividing both sides by 20:
y = -2
Now that we have the value of y, we can substitute it back into the first equation to find the value of x:
x = 7y
x = 7(-2)
x = -14
Therefore, the solution to the system of equations is x = -14 and y = -2.