Solve the system by substitution.
minus, 2, x, minus, 4, y, equals, minus, 18
−2x−4y=
−18
x, equals, y
x=
y
The given system of equations can be written as:
-2x - 4y = -18 (Equation 1)
x = y (Equation 2)
We can substitute Equation 2 into Equation 1 to solve for y:
-2(y) - 4y = -18
-2y - 4y = -18
-6y = -18
y = -18 / -6
y = 3
Now we substitute the value of y back into Equation 2 to solve for x:
x = 3
Therefore, the solution to the system of equations is x = 3 and y = 3.
To solve the system using substitution, we are given the equations:
1) minus 2x - 4y = -18
2) x = y
Let's solve the second equation (2) for x in terms of y:
x = y
Now let's substitute this value into the first equation (1):
-2(y) - 4y = -18
Simplifying the equation:
-2y - 4y = -18
-6y = -18
y = (-18) / (-6)
y = 3
Now plug this value back into the second equation (2) to find x:
x = y
x = 3
Therefore, the solution to the system of equations is x = 3 and y = 3.
To solve the system by substitution, we need to isolate one variable in one of the equations and substitute it into the other equation.
Given the system:
-2x - 4y = -18 ...(Equation 1)
x = y ...(Equation 2)
Step 1: Substitute x in Equation 1 with the value of y from Equation 2.
Replace x in Equation 1 with y:
-2(y) - 4y = -18
Simplify:
-2y - 4y = -18
-6y = -18
Step 2: Solve Equation 2 for x.
Given that x = y, we can substitute y back into Equation 2:
x = y
x = x (since x = y)
Step 3: Solve for y.
We have -6y = -18 from Step 1. To solve for y, divide both sides of the equation by -6:
-6y/-6 = -18/-6
y = 3
Step 4: Substitute the value of y into Equation 2 to solve for x.
x = y
x = 3
So the solution to the system is:
x = 3
y = 3