Given f(x)=4x2−10x−3 , according to the Remainder Theorem, f(2) can be found by finding the remainder of which of the following division quotients?(1 point)

Question

Given f(x)=4x2−10x−3 , according to the Remainder Theorem, f(2) can be found by finding the remainder of which of the following division quotients?(1 point)

Responses

(4x2−10x−3)÷(x+2)
left parenthesis 4 x squared minus 10 x minus 3 right parenthesis divided by left parenthesis x plus 2 right parenthesis

(4x2−10x−3)÷(x−2)
left parenthesis 4 x squared minus 10 x minus 3 right parenthesis divided by left parenthesis x minus 2 right parenthesis

(4x2−10x−3)÷x
left parenthesis 4 x squared minus 10 x minus 3 right parenthesis divided by x

(4x2−10x−3)÷2
left parenthesis 4 x squared minus 10 x minus 3 right parenthesis divided by 2

Answer 1

According to the Remainder Theorem, to find f(2), we need to divide f(x) by (x-2). Therefore, the correct division quotient is (4x^2-10x-3)÷(x-2).

Answer 2

According to the Remainder Theorem, to find f(2), we need to find the remainder of dividing (4x^2 - 10x - 3) by (x - 2). Thus, the correct division quotient is:

(4x^2 - 10x - 3) ÷ (x - 2)

Answer 3

According to the Remainder Theorem, in order to find f(2), we need to divide the polynomial f(x) = 4x^2 - 10x - 3 by (x - 2). Therefore, the correct division quotient to find f(2) is (4x^2 - 10x - 3) ÷ (x - 2).