Claire works two jobs; she works 54 hours in one week with these two jobs and makes $10 an hour. She is trying to save up for a trip that cost her $5000. She has set aside $1500 already. Write an inequality to represent the minimum amount of weeks she needs to work to save at least 5000. (1 point)
Responses
54(10)x+1500≥5000
54
(
10
)
x
+
1500
≥
5000
54 10 x plus 1500 is greater than or equal to 5000
54(10)x−1500≤5000
54
(
10
)
x
−
1500
≤
5000
54 10 x minus 1500 is less than or equal to 5000
10x+1500≥5000
10
x
+
1500
≥
5000
10 x plus 1500 is greater than or equal to 5000
10x+1500≤5000
10
x
+ 1500
≤
5000
10 x plus 1500 is less than or equal to 5000
10x + 1500 ≤ 5000
To solve this problem, we need to figure out how many weeks Claire needs to work in order to save at least $5000.
Let's break down the information given:
- Claire works 54 hours in one week.
- She earns $10 per hour.
- She has already saved $1500.
- She wants to save a total of $5000.
To find out how many weeks Claire needs to work, we need to calculate her total earnings per week, subtract her initial savings, and then divide the remaining amount by her earnings per week.
First, let's calculate her weekly earnings:
54 hours per week * $10 per hour = $540 per week
Next, let's subtract her initial savings from the total cost of the trip:
$5000 - $1500 = $3500
Now, to find the minimum amount of weeks Claire needs to work, we divide the remaining amount by her weekly earnings:
$3500 / $540 = approximately 6.48
Since we can't have a fraction of a week, we round up to the nearest whole number. Therefore, Claire needs to work at least 7 weeks to save at least $5000.
So, the correct inequality to represent the minimum amount of weeks she needs to work is:
54(10)x + 1500 >= 5000