you and your three friends are going to the State Fair. It’s costs $5 per person for admission into the fair and $3 for each ride. Which algebraic expression represents the TOTAL amount of money it will cost you for you and your three friends to get into the fair and ride “x” amount of rides? (2 points)
The algebraic expression that represents the total amount of money it will cost is:
$5(4) + $3(x)
Explanation:
- $5 is the cost per person for admission into the fair
- There are 4 people in total (you and your three friends)
- $3 is the cost per ride
- "x" represents the number of rides you choose to ride. Since each ride costs $3, the total cost of rides would be $3(x).
you and your three friends are going to the State Fair. It’s costs $5 per person for admission into the fair and $3 for each ride. Which algebraic expression represents the TOTAL amount of money it will cost you for you and your three friends to get into the fair and ride “x” amount of rides? (2 points)
responses
5x + 3
3x + 20
15x
3x + 5
The correct algebraic expression that represents the total amount of money it will cost is:
4(5) + 3(x)
Explanation:
- $5 is the cost per person for admission into the fair.
- There are 4 people in total (you and your three friends).
- $3 is the cost per ride.
- "x" represents the number of rides you choose to ride. Since each ride costs $3, the total cost of rides would be $3(x).
pick one
The algebraic expression that represents the total amount of money it will cost you for you and your three friends to get into the fair and ride "x" amount of rides is:
4(5) + 3(x)
which one out of the options i put bot
The correct algebraic expression out of the options you provided is:
3x + 5
At the fair there are two bean bag toss games. You gain 3/4 of a point for each bean bag that you get on the target and you lose 1/2 point for each bean bag that does not land on the target. Your total amount of points for this game can be represented by 3/4h - 1/2g. In a different bean bag toss game you gain 7/8 points for each bean bag that get on the target and you lose 3/4 points for each bean bag that does not land on the target. Your total amount of points for this game can be represented by 7/8h - 3/4g. You can figure out the total number of points earned by simplifying this expression: (3/4h - 1/2g) + (7/8h - 3/4g). What would this expression be simplified?
responses
10/14h - 4/6g
15/8h + 5/4g
1 5/8h
1 1/2h - 1 3/4g
To simplify the expression (3/4h - 1/2g) + (7/8h - 3/4g), we need to combine like terms.
First, let's combine the "h" terms: (3/4h + 7/8h). To add these fractions, we need a common denominator, which in this case is 8.
(3/4h + 7/8h) = (6/8h + 7/8h) = (13/8h)
Next, let's combine the "g" terms: (-1/2g - 3/4g). Again, we need a common denominator, which is 4.
(-1/2g - 3/4g) = (-2/4g - 3/4g) = (-5/4g)
Putting it all together, the simplified expression is:
(13/8h) + (-5/4g)
or
(13/8)h - (5/4)g
So, the simplified expression is 13/8h - 5/4g.
which one out of the options i pick bot
The correct simplified expression out of the options you provided is:
15/8h + 5/4g
Complete this fill-in-the-blank problem.
When you evaluate an expression, you substitute a number in for a ____. For example, to evaluate the expression 4y+3 for y=6, you would substitute 6 for “y”. You would then solve using the Order of Operations. So, 4(6)+3=____. You can also simplify algebraic expressions without knowing what the variables equal. For example, in this expression, (6k+5)+(3k-7). You would add together the coefficients (numbers) in front of “k” and add together the constants or numbers. Adding or subtracting the same variables together is called combining ____. So, you would combine 6k + 3k which would equal 9k and you would combine the constants, 5 + -7 which would equal ____.
When you evaluate an expression, you substitute a number in for a variable. For example, to evaluate the expression 4y + 3 for y = 6, you would substitute 6 for "y". You would then solve using the Order of Operations. So, 4(6) + 3 = ____.
You can also simplify algebraic expressions without knowing what the variables equal. For example, in this expression, (6k + 5) + (3k - 7). You would add together the coefficients (numbers) in front of "k" and add together the constants or numbers. Adding or subtracting the same variables together is called combining like terms. So, you would combine 6k + 3k, which would equal 9k, and you would combine the constants, 5 + (-7), which would equal ____.
can you pls answer all the blank problems
Certainly! Here are the answers to the blank problems:
- So, 4(6) + 3 = 24 + 3 = 27
- In the expression (6k + 5) + (3k - 7), combining like terms gives us 9k + (-2), which can be written as 9k - 2.
Complete this fill-in-the-blank problem.
When you evaluate an expression, you substitute a number in for a ____. For example, to evaluate the expression 4y+3 for y=6, you would substitute 6 for “y”. You would then solve using the Order of Operations. So, 4(6)+3=____. You can also simplify algebraic expressions without knowing what the variables equal. For example, in this expression, (6k+5)+(3k-7). You would add together the coefficients (numbers) in front of “k” and add together the constants or numbers. Adding or subtracting the same variables together is called combining ____. So, you would combine 6k + 3k which would equal 9k and you would combine the constants, 5 + -7 which would equal ____.
Fill in ALL the blanks
When you evaluate an expression, you substitute a number in for a variable. For example, to evaluate the expression 4y + 3 for y = 6, you would substitute 6 for "y". You would then solve using the Order of Operations. So, 4(6) + 3 = 24 + 3 = 27.
You can also simplify algebraic expressions without knowing what the variables equal. For example, in this expression, (6k + 5) + (3k - 7). You would add together the coefficients (numbers) in front of "k" and add together the constants or numbers. Adding or subtracting the same variables together is called combining like terms. So, you would combine 6k + 3k, which would equal 9k, and you would combine the constants, 5 + (-7), which would equal -2.
At the state fair you buy 4 combo meals for you and your three friends. Each meal comes with three chicken tenders and two fried Oreos how many chicken tenders and fried Oreos do you buy all together? How could you set up and solve this problem using distributive property
To set up and solve this problem using the distributive property, we can use the fact that there are 4 combo meals, with each meal consisting of 3 chicken tenders and 2 fried Oreos.
To find the total number of chicken tenders, we can distribute the number of combo meals (4) to the number of chicken tenders in each meal (3). This can be expressed as 4 * 3 = 12 chicken tenders.
Similarly, to find the total number of fried Oreos, we can distribute the number of combo meals (4) to the number of fried Oreos in each meal (2). This can be expressed as 4 * 2 = 8 fried Oreos.
Therefore, all together, you buy 12 chicken tenders and 8 fried Oreos at the state fair.
Part one: at the state fair it cost $2.75 for a corn dog and $3.50 for a funnel cake. How much would it cost for you to order C corn dogs and F funnel cakes show how to set this up an algebraic expression.
Part 2: you and your three friends want to order two corn dogs, and one funnel cake, each solve to find out how much it would cost altogether.
Part 3: Explain how you solved part 2
Part 1: To set up an algebraic expression for the cost of ordering C corn dogs and F funnel cakes, we can multiply the number of corn dogs by the cost of each corn dog ($2.75) and multiply the number of funnel cakes by the cost of each funnel cake ($3.50). The algebraic expression would be:
Cost = C * $2.75 + F * $3.50
Part 2: To find out how much it would cost for you and your three friends to order two corn dogs and one funnel cake each, we need to substitute the values into the algebraic expression.
Cost = 2 * $2.75 + 1 * $3.50
= $5.50 + $3.50
= $9.00
Therefore, it would cost $9.00 altogether for you and your three friends to order two corn dogs and one funnel cake each.
Part 3: I solved part 2 by substituting the number of corn dogs (2) and the number of funnel cakes (1) into the algebraic expression for the cost. I then used the distributive property to multiply the number of corn dogs by the cost per corn dog and multiply the number of funnel cakes by the cost per funnel cake. Finally, I added the two resulting products together to find the total cost.