The following recursive function will print the nth power of 2. def powerOf2(n): if n == 0: return 1 else: return (2 * powerOf2(n - 1)) (1 point) Responses Image with alt text: A rectangle is labeled ‘power Of 2 left parenthesis n right parenthesis.’ An arrow originates from the rectangle connects to a rhombus. The rhombus is labeled ‘n equals equals 0.’ Two arrows originate from the rhombus. An arrow labeled ‘Yes’ connects to a rectangle labeled ‘Return 2 superscript n baseline.’ Another arrow labeled ‘No’ connects to a rectangle labeled ‘left parenthesis n right parenthesis equals left parenthesis n minus 1 right parenthesis.’ An arrow originates from this rectangle and connects to the first rectangle labeled ‘power Of 2 left parenthesis n right parenthesis.’ Image with alt text: A rectangle is labeled ‘power Of 2 left parenthesis n right parenthesis.’ An arrow originates from the rectangle connects to a rhombus. The rhombus is labeled ‘n equals equals 0.’ Two arrows originate from the rhombus. An arrow labeled ‘Yes’ connects to a rectangle labeled ‘Return 1.’ Another arrow labeled ‘No’ connects to a rectangle labeled ‘left parenthesis n right parenthesis equals left parenthesis n minus 1 right parenthesis.’ An arrow originates from this rectangle and connects to the first rectangle labeled ‘power Of 2 left parenthesis n right parenthesis.’ Image with alt text: A rectangle is labeled ‘power Of 2 left parenthesis n right parenthesis.’ An arrow originates from the rectangle connects to a rhombus. The rhombus is labeled ‘n equals equals 2.’ Two arrows originate from the rhombus. An arrow labeled ‘Yes’ connects to a rectangle labeled ‘Return 1.’ Another arrow labeled ‘No’ connects to a rectangle labeled ‘left parenthesis n right parenthesis equals left parenthesis n minus 1 right parenthesis.’ An arrow originates from this rectangle and connects to the first rectangle labeled ‘power Of 2 left parenthesis n right parenthesis.’
The correct response is:
Image with alt text: A rectangle is labeled ‘power Of 2 left parenthesis n right parenthesis.’ An arrow originates from the rectangle connects to a rhombus. The rhombus is labeled ‘n equals equals 0.’ Two arrows originate from the rhombus. An arrow labeled ‘Yes’ connects to a rectangle labeled ‘Return 1.’ Another arrow labeled ‘No’ connects to a rectangle labeled ‘left parenthesis n right parenthesis equals left parenthesis n minus 1 right parenthesis.’ An arrow originates from this rectangle and connects to the first rectangle labeled ‘power Of 2 left parenthesis n right parenthesis.’
The first response appears to be the accurate one because it shows the correct logic for the recursive function "powerOf2(n)". It shows the base case where n equals 0, and the recursive step where the function calls itself with n-1. This recursive step is used to calculate the power of 2 by multiplying the result of the previous call with 2.
The given recursive function calculates the nth power of 2. Here is how the function works step by step:
1. The function is called with a parameter n.
2. It checks if the value of n is equal to 0. If it is, this means we have reached the base case, and the function returns 1. This is because any number raised to the power of 0 is always 1.
3. If the value of n is not equal to 0, the function makes a recursive call to itself with the argument n - 1. This means that it calculates the (n-1)th power of 2 and multiplies it by 2 to get the nth power.
4. The result of the recursive call is returned as the output of the function.
To use this function, you would call it with the desired value of n, like this: powerOf2(n).
The images you provided illustrate the flow of the function using a flowchart. Both images show the same logic, but with different labeling. The rectangles represent actions or calculations, while the rhombus represents a decision or condition based on n.
I hope this explanation helps! Let me know if you have any further questions.