The weight of an ant averages about 3×10^−6 kg. There are about 1×10^16 ants in the world. What is the approximate weight in kilograms of all the ants in the world? Write the answer in scientific notation.(1 point)
To find the approximate weight of all the ants in the world, we can multiply the average weight of an ant by the number of ants.
Weight of one ant: 3×10^−6 kg
Number of ants in the world: 1×10^16 ants
Weight of all ants in the world = (3×10^−6 kg) * (1×10^16 ants)
When multiplying numbers in scientific notation, we add the exponents and multiply the coefficients:
Weight of all ants in the world = 3 * 1 * 10^(-6 + 16)
= 3 * 10^10 kg
So, the approximate weight of all the ants in the world is 3 * 10^10 kg.
The average human heart beats about 3.5×10^7 times per year. The current population of Massachusetts is about 7×10^6 people. About how many heartbeats occur in Massachusetts per year? Write the answer in scientific notation. Express the answer to the exact decimal place.(1 point)
To find the approximate number of heartbeats in Massachusetts per year, we can multiply the average number of heartbeats per person by the population of Massachusetts.
Heartbeats per person per year: 3.5×10^7 times
Population of Massachusetts: 7×10^6 people
Number of heartbeats in Massachusetts per year = (3.5×10^7 times/person/year) * (7×10^6 people)
When multiplying numbers in scientific notation, we add the exponents and multiply the coefficients:
Number of heartbeats in Massachusetts per year = 3.5 * 7 * 10^(7 + 6) times
= 24.5 * 10^13 times
So, approximately 24.5 * 10^13 heartbeats occur in Massachusetts per year.
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Apologies for the mistake.
To find the approximate number of heartbeats in Massachusetts per year, we can multiply the average number of heartbeats per person by the population of Massachusetts.
Heartbeats per person per year: 3.5×10^7 times
Population of Massachusetts: 7×10^6 people
Number of heartbeats in Massachusetts per year = (3.5×10^7 times/person/year) * (7×10^6 people)
When multiplying numbers in scientific notation, we add the exponents and multiply the coefficients:
Number of heartbeats in Massachusetts per year = 3.5 * 7 * 10^(7 + 6) times
= 24.5 * 10^13 times
So, approximately 24.5 * 10^13 heartbeats occur in Massachusetts per year.
The sun generates about 4×1026 joules of energy every second. There are about 3.15×107 seconds in a year. About how many joules of energy does the sun generate in a year? Write the answer in scientific notation. Express the answer to the exact decimal place.(1 point)
To find the approximate amount of energy the sun generates in a year, we can multiply the energy generated per second by the number of seconds in a year.
Energy generated per second: 4×10^26 joules
Number of seconds in a year: 3.15×10^7 seconds
Energy generated by the sun in a year = (4×10^26 joules/second) * (3.15×10^7 seconds)
When multiplying numbers in scientific notation, we add the exponents and multiply the coefficients:
Energy generated by the sun in a year = 4 * 3.15 * 10^ (26 + 7) joules
= 12.6 * 10^33 joules
So, approximately 12.6 * 10^33 joules of energy are generated by the sun in a year.
In a given year, about 1.52×1010 pieces of first-class mail are delivered in the U.S. If each piece of mail carries a stamp costing $0.55, what is the total cost in dollars to deliver all the pieces? Write the answer in scientific notation, expressed to the exact decimal place.(1 point)
To find the total cost to deliver all the pieces of first-class mail in the U.S., we can multiply the number of pieces of mail by the cost of a stamp.
Number of pieces of mail: 1.52×10^10
Cost of a stamp: $0.55
Total cost to deliver all the pieces of mail = (1.52×10^10 pieces) * ($0.55/piece)
When multiplying numbers in scientific notation, we multiply the coefficients and add the exponents:
Total cost to deliver all the pieces of mail = 1.52 * 0.55 * 10^10 dollars
= 0.836 * 10^10 dollars
So, the total cost to deliver all the pieces of first-class mail in the U.S. is approximately 0.836 * 10^10 dollars.
To find the approximate weight of all the ants in the world, we need to multiply the average weight of an ant by the total number of ants.
The average weight of an ant is given as 3×10^(-6) kg.
The total number of ants in the world is given as 1×10^16.
To multiply the two numbers, we can simply multiply the coefficients (3 and 1) and add the exponents of 10 (-6 and 16).
3×10^(-6) * 1×10^16 = 3×1×10^(-6+16) = 3×10^10
Therefore, the approximate weight of all the ants in the world is 3×10^10 kg (in scientific notation).