The weight of an ant averages about 3×10^−6 kg. There are about 1×10^16 ants in the world. What is the approximate weight in kilograms of all the ants in the world? Write the answer in scientific notation.(1 point)

All of them are correct except for number 1, which the answer was actually 1.21×10^-3

To find the approximate weight of all the ants in the world, we can multiply the weight of one ant by the total number of ants.

Weight of one ant = 3×10^−6 kg

Number of ants in the world = 1×10^16 ants

Weight of all the ants in the world = (3×10^−6 kg) × (1×10^16 ants)

To find the product of these numbers, we can add the exponents and keep the base 10:

(3×1) × (10^(-6+16))

= 3 × 10^10

Therefore, the approximate weight in kilograms of all the ants in the world is 3 × 10^10 kg.

The average human heart beats about 3.5×10^7 times per year. The current population of Massachusetts is about 7×10^6 people. About how many heartbeats occur in Massachusetts per year? Write the answer in scientific notation. Express the answer to the exact decimal place.(1 point)

To find the number of heartbeats that occur in Massachusetts per year, we need to multiply the average number of heartbeats per person by the population of Massachusetts.

Average number of heartbeats per person per year = 3.5×10^7

Population of Massachusetts = 7×10^6 people

Number of heartbeats in Massachusetts per year = (3.5×10^7) × (7×10^6)

To find the product of these numbers, we can add the exponents and keep the base 10:

(3.5 × 7) × (10^(7+6))

= 24.5 × 10^13

Therefore, the number of heartbeats that occur in Massachusetts per year is 24.5 × 10^13.

Bot, Write the answer in scientific notation. Express the answer to the exact decimal place.

I apologize for the mistake. To express the answer in scientific notation with the exact decimal place, we can rewrite as:

Number of heartbeats in Massachusetts per year = 2.45 × 10^14

Therefore, the number of heartbeats that occur in Massachusetts per year is approximately 2.45 × 10^14.

The sun generates about 4×10^26 joules of energy every second. There are about 3.15×10^7 seconds in a year. About how many joules of energy does the sun generate in a year? Write the answer in scientific notation. Express the answer to the exact decimal place.(1 point)

To find the number of joules of energy the sun generates in a year, we need to multiply the energy generated per second by the number of seconds in a year.

Energy generated per second by the sun = 4×10^26 joules

Number of seconds in a year = 3.15×10^7 seconds

Joules of energy generated by the sun in a year = (4×10^26) × (3.15×10^7)

To find the product of these numbers, we can add the exponents and keep the base 10:

(4 × 3.15) × (10^(26+7))

= 12.6 × 10^33

Therefore, the number of joules of energy that the sun generates in a year is approximately 12.6 × 10^33.

Bot, Write the answer in scientific notation. Express the answer to the exact decimal place

To express the answer in scientific notation with the exact decimal place, we have:

Joules of energy generated by the sun in a year = 1.26 × 10^34

Therefore, the number of joules of energy that the sun generates in a year is approximately 1.26 × 10^34.