If the expression 715 was simplified using the Power Rule of Exponents, which of the following would be an expanded equivalent expression?(1 point) Responses (718)3 left parenthesis 7 superscript 18 baseline right parenthesis cubed (7⋅7⋅7⋅7⋅7)10 left parenthesis 7 times 7 times 7 times 7 times 7 right parenthesis superscript 10 baseline (710)5 left parenthesis 7 superscript 10 baseline right parenthesis superscript 5 baseline (7⋅7⋅7)⋅(7⋅7⋅7)⋅(7⋅7⋅7)⋅(7⋅7⋅7)
If the expression 715 was simplified using the Power Rule of Exponents, the expanded equivalent expression would be:
(7⋅7⋅7⋅7⋅7)⋅(7⋅7⋅7⋅7⋅7)⋅(7⋅7⋅7⋅7⋅7)
what about 7v25
If the expression 7^25 was simplified using the Power Rule of Exponents, the expanded equivalent expression would be:
7⋅7⋅7⋅7⋅7⋅7⋅7⋅7⋅7⋅7⋅7⋅7⋅7⋅7⋅7⋅7⋅7⋅7⋅7⋅7⋅7⋅7⋅7⋅7⋅7⋅7
7v15
If the expression 7^15 was simplified using the Power Rule of Exponents, the expanded equivalent expression would be:
7⋅7⋅7⋅7⋅7⋅7⋅7⋅7⋅7⋅7⋅7⋅7⋅7⋅7⋅7
The expanded equivalent expression of the simplified expression 715 using the Power Rule of Exponents is:
(7⋅7⋅7)⋅(7⋅7⋅7)⋅(7⋅7⋅7)⋅(7⋅7⋅7)
To find the expanded equivalent expression of 715 using the Power Rule of Exponents, we need to break down 715 into its prime factors.
To do this, we start by finding the factors of 715:
715 = 5 × 11 × 13
Now, let's express each factor with exponents:
715 = 5^1 × 11^1 × 13^1
Applying the Power Rule of Exponents, we can expand this expression:
715 = (5^1 × 11^1 × 13^1)
Therefore, the expanded equivalent expression of 715 using the Power Rule of Exponents is: (5^1 × 11^1 × 13^1), which is option d) (7⋅7⋅7)⋅(7⋅7⋅7)⋅(7⋅7⋅7)⋅(7⋅7⋅7).