A fire engine's water tank holds 750 gallons of water. If the pump removes 250 gallons of water in 5 minutes, what is the change in the amount of water in gallons in 1 minute
The pump removes 250 gallons of water in 5 minutes.
So, in 1 minute, the pump removes 250/5 = <<250/5=50>>50 gallons of water.
Therefore, the change in the amount of water in 1 minute is 50 gallons. Answer: \boxed{50}.
To find the change in the amount of water in 1 minute, we can calculate the rate at which the pump removes water.
Rate = Amount of water / Time
In this case, the pump removes 250 gallons of water in 5 minutes, so:
Rate = 250 gallons / 5 minutes = 50 gallons/minute
Therefore, the change in the amount of water in 1 minute is 50 gallons.
To find the change in the amount of water in 1 minute, we need to determine how many gallons of water the pump removes in 1 minute.
Given that the pump removes 250 gallons of water in 5 minutes, we can calculate the rate at which the pump removes water by dividing the number of gallons by the number of minutes:
Rate = 250 gallons / 5 minutes
Rate = 50 gallons/minute
Therefore, in 1 minute, the pump removes 50 gallons of water from the fire engine's water tank.