If you have 3.78 g
of H2
, how many grams of NH3
can be produced?
Express your answer with the appropriate units.If you have 3.78 g
of H2
, how many grams of NH3
can be produced?
Express your answer with the appropriate units.
The balanced chemical equation for the reaction between H2 and NH3 is:
3H2 + N2 -> 2NH3
From the equation, we can see that 3 moles of H2 react to form 2 moles of NH3.
To convert grams of H2 to grams of NH3, we need to use the molar mass and stoichiometry of the reaction.
The molar mass of H2 is 2.02 g/mol, and the molar mass of NH3 is 17.03 g/mol.
First, calculate the number of moles of H2:
moles H2 = 3.78 g / 2.02 g/mol = 1.871 mol
Now, using the stoichiometry of the reaction, we can determine the number of moles of NH3 that can be produced:
moles NH3 = (2 moles NH3 / 3 moles H2) * 1.871 mol H2 = 1.247 mol
Finally, convert moles of NH3 to grams:
grams NH3 = moles NH3 * molar mass NH3 = 1.247 mol * 17.03 g/mol = 21.22 g
Therefore, 3.78 g of H2 can produce 21.22 g of NH3.
To determine the number of grams of NH3 that can be produced, we need to use the stoichiometry of the balanced chemical equation for the reaction.
The balanced chemical equation for the reaction between H2 and NH3 is:
3 H2 + N2 -> 2 NH3
From the equation, we can see that 3 moles of H2 react with 1 mole of N2 to produce 2 moles of NH3.
To calculate the number of moles of H2, we use the formula:
moles = mass / molar mass
The molar mass of H2 is 2 g/mol.
moles of H2 = 3.78 g / 2 g/mol = 1.89 mol
Now, using the stoichiometry of the equation, we can determine the moles of NH3 that can be produced. From the equation, we know that 3 moles of H2 reacts to produce 2 moles of NH3.
moles of NH3 = (moles of H2 / 3) * 2 = (1.89 mol / 3) * 2 = 1.26 mol
Finally, we calculate the grams of NH3 using the formula:
mass = moles * molar mass
The molar mass of NH3 is 17 g/mol.
mass of NH3 = 1.26 mol * 17 g/mol = 21.42 g
Therefore, if you have 3.78 g of H2, you can produce 21.42 g of NH3.
To calculate the amount of NH3 that can be produced from a given amount of H2, we need to determine the balanced chemical equation for the reaction between H2 and NH3.
The balanced chemical equation for the reaction is:
3H2 + N2 → 2NH3
From the balanced equation, we can see that 3 moles of H2 react to produce 2 moles of NH3. This means that there is a stoichiometric ratio of 3:2 between H2 and NH3.
To determine the number of moles of H2 in 3.78 g, we need to use the molar mass of H2, which is 2 g/mol. So, the moles of H2 can be calculated using the formula:
moles of H2 = (mass of H2) / (molar mass of H2)
moles of H2 = 3.78 g / 2 g/mol
moles of H2 = 1.89 mol
Using the stoichiometric ratio, we can calculate the moles of NH3 that can be produced:
moles of NH3 = (moles of H2) x (2 moles of NH3 / 3 moles of H2)
moles of NH3 = 1.89 mol x (2/3)
moles of NH3 = 1.26 mol
Finally, we can determine the mass of NH3 using its molar mass, which is 17 g/mol. So, the mass of NH3 is:
mass of NH3 = (moles of NH3) x (molar mass of NH3)
mass of NH3 = 1.26 mol x 17 g/mol
mass of NH3 = 21.42 g
Therefore, if you have 3.78 grams of H2, you can produce 21.42 grams of NH3.